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Sliva [168]
3 years ago
12

Solve this inequality: j/4 – 8 < 4.

Mathematics
1 answer:
fredd [130]3 years ago
4 0
The answer to this is c
j<48
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What is the answer to this question
vlada-n [284]

Answer:

B

Step-by-step explanation:

If you calculate the side of a square using pythagorean theorem, you would get a side length of sqrt37. Simple multiply this by 4

8 0
3 years ago
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What is the value of y in the solution to the following system of equations? 5x − 3y = −11 2x − 6y = −14 −1 0 1 2
Alekssandra [29.7K]
5x - 3y = -11 (×2)
2x - 6y = -14 (x5)

10x - 6y = -22
10x - 30y = -70
---------------------- -
24y = 48
y = 2
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The campsite is square in shape and has a length of 65 metres.<br> What is the area of the campsite?
IgorLugansk [536]
65x65=4225
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3 years ago
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What is the measure of angle BAC ?
Eva8 [605]
An inscribed angle (BAC) is one half the angle of a central angle (BOC) that intercepts the same arc.  Therefore, BAC = 34 degrees.


3 0
3 years ago
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For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
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