Help?? I need that question to but just that the weight instead of being 1000 is 2000
Answer with Step-by-step explanation:
Let F be a field .Suppose 
and 
We have to prove that a has unique multiplicative inverse.
Suppose a has two inverses b and c
Then, 
where 1 =Multiplicative identity
(cancel a on both sides)
Hence, a has unique multiplicative inverse.
Answer:
damm its tuff to not know anything
Step-by-step explanation:
<em>θ</em> is given to be in the fourth quadrant (270° < <em>θ</em> < 360°) for which sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. This means
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1 ==> sin(<em>θ</em>) = -√[1 - cos²(<em>θ</em>)] = -3/5
Now recall the double angle identity for sine:
sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)
==> sin(2<em>θ</em>) = 2 (-3/5) (4/5) = -24/25
