Answer:
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Step-by-step explanation:
we have
![f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)

we know that
In the function

The variable of the function f is now the function g(x)
substitute
![f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%7D%7D)
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Answer:
error
Step-by-step explanation:
Answer:
BC 1
AC 2
AABC 3
Step-by-step explanation:
BC=16
AC = 15
AABC= 15
7 1/4 - 2 4/5
Turn the denominator into a common denominator for both fractions:
7 5/20 - 2 16/20
To subtract easier, turn the fractions into an improper fraction:
145/20 - 56/20
Subtract the numerators:
145 - 56 = 89 ---> 89/20
Simplify (to get an answer of):
4 9/20
Add labels:
Joseph has 4 9/20 ounces of candy left