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So there are five candy bars.
Herself and two sisters equals 3 people in total.
This is a graph of 5 candy bars, each line being 1/2.
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━ ━
━ ━
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━ ━
If she ate half of one... the graph would become this.
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━
Now there are 9 halves. You need to split the 9 halves for 3 people. 9 divided by 3 is 3.
Each person gets 3 halves, or 1 and 1 half.
Mai: ━ ━ ━
Sister 1: ━ ━ ━
Sister 2: ━ ━ ━
Altogether that is 9 halves, AKA the number of halves Mai had after she ate 1/2.
The amount Mai ate in the first place: ━
9 halves plus 1 half, equals 10 halves. Each whole has 2 halves. 10 divided by 2 is 5, AKA the number of candy bars she had in the first place.
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(x cookies) / (23 students - (12/2) students) = 2 cookies per student
[x / (23 - 6)] cookies per student = 2 cookies per student
23 students * (2 cookies per students) - 12 cookies = x cookies
The "students" unit cancels
46 cookies - 12 cookies = x cookies
x cookies = 34 cookies
For the volume, the formula is length*width*height
so
<span><span><span>(2)</span><span>(1.5)</span></span><span>(1.5)</span></span><span>=<span>4.5
In other words, your answer would be 4.5</span></span>
Answer:
i have no clew
Step-by-step explanation:
Answer:
- 6.04 km (per angle marks)
- 5.36 km (per side hash marks)
Step-by-step explanation:
Going by the angle indicators, the ratios of corresponding sides of the similar triangles are ...
x/2000 = 4200/3500
x = 2000·6/5 = 2400 . . . . yards
Then the distance of interest is ...
(2400 yd + 4200 yd)×(0.0009144 km/yd) = 6.6×.9144 km
= 6.03504 km ≈ 6.04 km
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Going by the red hash marks, the ratios of corresponding sides of the similar triangles are ...
x/2000 = 3500/4200
x = 2000·(5/6) = 5000/3 . . . . yards
Then the distance of interest is ...
(5000/3 + 4200) yd × 0.0009144 km/yd ≈ 5.36 km
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<em>Comment on the figure</em>
The usual geometry here is that the outside legs (opposite the vertical angles) are parallel, meaning that the angle indicators are the correct marks. It is possible, but unusual, for the red hash marks to be correct and the angle indicators to be mismarked. The red hash marks seem tentatively drawn, so seem like they're more likely to be the incorrect marks.
