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3 years ago

The radius of one sphere measures twice the length of another. The ratio of their surface areas is

Mathematics

2 answers:

Katena32 [7]3 years ago

6 0

Answer:

4:1

Step-by-step explanation:

Alex787 [66]3 years ago

4 0

4:1
Because the ratio of areas is the ratio of the radii (or diameters) squared.

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Can I please have some help????

DedPeter [7]

Answer:

avn= -8 + (n-1)(-7)

Step-by-step explanation:

arithmetic sequence formula= avn= av1 + (n-1)d

av1= first number in the sequence

d= common difference

n= the number of the term to find

The common difference is -7 so d=-7 and you plug it into the equation. The first number in the sequence is -8 so av1.

There is no specific n to find so it remains n.

I hope this helps! Let me know if this helps.

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2 years ago

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each question mark is a missing exponent. find the value of the exponent and match each correct answer to complete the riddle be

alukav5142 [94]

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7 0

2 years ago

A service attendant is paid time and a 1/2 for working over 40 hours per week last week. The attendant work 47 hours and earned

devlian [24]

Write and solve an equation:

Total earnings = $782.75 = s(40 hrs) + 1.5*s*(7 hrs)

Then 782.75 = 40s + 10.5s = 50.5s

Dividing both sides by 50.5: s = 15.5. The attendant's regular hourly wage was $15.50.

5 0

3 years ago

THE ANSWER I PUT IS JUST A GUESS, IF IT ISN'T THE ANSWER PLEASE TELL ME WHAT IT IS I BEG YOU

Anna [14]

Answer:

the first one

Step-by-step explanation:

can you help me with my question

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3 years ago

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At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the

Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).

Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:

Rope Needed = 23 + 2w < 39

Simplifying:

$23 + 2w < 39\\2w < 39 - 23\\2w < 16\\w < 8$

The range of possible values of w is $w$ meters (of course w has to be greater than 0)

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3 years ago