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4 years ago

What direction is the net force on a falling skydiver before she reaches terminal velocity?

Physics

1 answer:

GarryVolchara [31]4 years ago

8 0

Answer:

The net force and the acceleration on the falling skydiver is upward

Explanation:

An upward net force on a downward falling object would cause that object to slow down. the skydiver this slows down. As the speed decreases, the amount of air resistance also decreases until once more the skydiver reaches a terminal velocity.

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What factors affect the frictional force between objects ?

g100num [7]

Well it should be Material and weight not sure

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3 years ago

After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average

alexira [117]

Answer:

Incomplete Question

Explanation:

String constant is not stated

I'll solve this in a general way.

At the end of my explanation, I'll assume any value for string constant.

The total weight on the taptap : Weight of people + Weight of goats + Weight of chickens + weight of banana

= (25 * 66) + (3 * 15) + (5 * 3) + 25 = 1735 kg

The gravitational force exerted on the taptap

Fig = m*g

where m = the total mass 1735kg

and g = 9.8m/s²

Hooke's law of Elasticity states that

Fs = Kx

Where Fs = spring force

k = spring constant

x = spring stretch or compression

Since Fs = Fg

So, Kx = mg

Make x the subject of the formula

x = mg/k --------------- This is the general way of solving for spring compressor in cases like this

I'll replace m and g with their values, respectively.

Because, the spring constant (k) is omitted in the question, I'll assume it to be 30000

x = 1735 * 9.8/30000

x = 17003/30000

x = 0.566767 metres

x = 0.57 metres ------------- Approximated

In conclusion, the spring compression is 0.57 metres if the spring constant is 30000

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3 years ago

What is a magnetic field?

monitta

A magnetic field is charged electricity acting in the forced of magnatism

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3 years ago

The instrument used to measure the diameter of a thin wire is

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micrometer is used to measure the diameter of a thin wire

3 0

4 years ago

Read 2 more answers

One point of the circuit is grounded (V = 0). What are the (a) size and (b) direction (up or down) of the current through resist

Svetach [21]

<h3>Answer:</h3>

(a) <u>i₁ = 0.03818 A = 38.18 mA</u>

(b) downward

(c) <u>i₂ = 0.01091 A = 10.91 mA</u>

(d) rightward

(e) <u>i₃ = 0.02727 A = 27.27 mA</u>

(f) leftward

(g) <u>Eₐ = 3.818 Volts</u>

<h3>Question:</h3>

The complete question is stated below and the figure is provided in the attachment:

In Fig. 27-47, E 1 = 6.00 V, E 2 = 12.0 V, R1 = 100 Ω,

R2 = 200 Ω, and R3 = 300 Ω. One point of the circuit is grounded

(V = 0). What are the (a) size and (b) direction (up or down) of the

current through resistance 1, the (c) size and (d) direction

(left or right) of the current through resistance 2, and the

(e) size and (f) direction of the current through resistance 3?

(g) What is the electric potential at point A?

<h3></h3><h3>Explanation:</h3>

Applying Kirchoff's voltage law in the loops of botg E₁ and E₂, in the clockwise and anti clockwise direction:

E₁ - i₂R₂ - i₁R₁ = 0

E₂ - i₃R₃ - i₁R₁ = 0

If, we apply Kirchhoff's current law at junction A, we get:

i₁ = i₂ + i₃

Using these relations in loop equations, and re-arranging:

E₁ - i₂R₂ - (i₂ + i₃) R₁ = 0 ___________ eqn (1)

E₂ - i₃R₃ - (i₂ + i₃) R₁ = 0 ___________ eqn (2)

Eqn (1) implies:

6 - 200 i₂ - 100 i₂ - 100 i₃ = 0

i₂ = (6 - 100i₃)/300

Eqn (2) implies:

12 - 300 i₃ - 100 i₂ - 100 i₃ = 0

12 - 400 i₃ = 100 i₂

using value of i₃ from eqn (1)

12 - 400 i₃ = (1/3)(6 - 100 i₃)

36 - 1200 i₃ = 6 - 100 i₃

1100 i₃ = 30

using this value in eqn of i₂:

i₂ = [6 - 100(0.02727)]/300

i₂ = (6 - 2.727)/300

Since:

i₁ = i₂ + i₃

i₁ = 0.01091 A + 0.02727 A

<u></u>

(a)

(b)

Since, the value of current is positive, thus it will have the direction that was assumed.

Therefore, its direction will <u>downward</u>

(c)

(d)

Since, the value of current is positive, thus it will have the direction that was assumed.

Therefore, its direction will <u>rightward</u>

(e)

(f)

Since, the value of current is positive, thus it will have the direction that was assumed.

Therefore, its direction will <u>leftward</u>

With respect to the grounded portion, the potential drop at the resistance 1 will be equal to the potential at A Eₐ.

Therefore,

Eₐ = i₁R₁

Eₐ = (0.03818 A)(100 Ω)

<u>Eₐ = 3.818 Volts</u>

3 0

4 years ago