The equation that would allow us to calculate for the acceleration given the distance is written below,
a = (Vf² - Vo²) / 2d
where a is the acceleration, Vf is the final velocity, Vo is the initial velocity, and d is distance.
Substituting the known values,
a = ((84 ft/s)² - (72 ft/s)²) / 2(180 ft) = 5.2 ft/s²
Then, the equation that would relate the initial velocity, distance, acceleration and time is calculated through the equation,
d = Vot + 0.5at²
Substituting the known values,
180 = 72(t) + 0.5(5.2)(t²)
The value of t from the equation is 2.3 s
<em>ANSWER: 2.3 s</em>
11. aboard
12. marsh
13. swore
14. starch
15. barge
16.swear
17. coarse
please vote my answer brainliest! thanks.
Answer:
4.86 m
Explanation:
Given that,
The frequency produced by a humming bird, f = 70 Hz
The speed of sound, v = 340 m/s
We need to find how far does the sound travel between wing flaps. Let the distance is equal to its wavelength. So,
So, the sound travel 4.86 m between wings flaps.
Answer:
drawing because Fine motor skills are the ability to make movements using the small muscles in our hands and wrists.
