First find the slope of A.
Slope=(y2-y1)/(x2-x1)=(4-0)/(0--7)=4/7
For a line to be perpendicular to line A, it must have a slope that is the negative reciprocal of the slope of A. Mathematically:
m1*m2=-1 and in this case the perpendicular line will have a slope of:
4m/7=-1
4m=-7
m=-7/4
So the slope of the line perpendicular to A is -7/4
Answer:
60 and 25
Step-by-step explanation:
The range is the difference between the maximum value and the minimum value.
maximum value = 125, minimum value = 65
range = 125 - 65 = 60
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The interquartile range is the difference between the upper quartile Q₃ and the lower quartile Q₁
Q₃ is the value at the right side of the box = 115
Q₁ is the value at the left side of the box = 90
interquartile range = 115 - 90 = 25
33 1/3 because it if you times it by 3, you get 100
Answer:
f(5)+2
Step-by-step explanation:
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