TConsider △RST and △RYX.
1 answer:
For similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.
Given that, for ΔRST, line XY is drawn parallel to side ST within ΔRST to form ΔRYX.
Considering ΔRST and ΔRYX.
<h3>What is the relation between sides of similar triangles?</h3>The corresponding sides of similar triangles are proportional.
We get ∠RXY=∠RST (Corresponding angles, since XY║ST)
∠RYX=∠RTS (Corresponding angles, since XY║ST)
From AA similarity criteria ΔRST is similar to ΔRYX.
Now, RY/RS = RX/RT = XY/TS.
Therefore, for similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.
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