TConsider △RST and △RYX.
1 answer:
For similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.
Given that, for ΔRST, line XY is drawn parallel to side ST within ΔRST to form ΔRYX.
Considering ΔRST and ΔRYX.
<h3>What is the relation between sides of similar triangles?</h3>The corresponding sides of similar triangles are proportional.
We get ∠RXY=∠RST (Corresponding angles, since XY║ST)
∠RYX=∠RTS (Corresponding angles, since XY║ST)
From AA similarity criteria ΔRST is similar to ΔRYX.
Now, RY/RS = RX/RT = XY/TS.
Therefore, for similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.
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Answer:
x = .23
x = 1.43
Step-by-step explanation:
1. The root of a polynomial is when the y-value equals 0. So set the equation euqal to 0:
2. Solve with the quadratic formula and you get:
and
which is x = .23 and x = 1.43.
Answer:
113.1 unit²
Step-by-step explanation:
A cylinder is a shape with two round ends and two parallel lines connecting the round ends.
Height=9 unit, Base=4 unit
The lateral surface area of a cylinder (A) is given by the equation:
where r is the radius of the cylinder and h is the height of the cylinder.
Given that the base = 4 unit, therefore the diameter (d) = base = 4 unit. Also the height (h) = 9 unit.
Radius (r) = d/2 = 4/2 = 2 unit
Calculating the area of the cylinder is as follows
The area of the cylinder is 113.1 unit²