For similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.
Given that, for ΔRST, line XY is drawn parallel to side ST within ΔRST to form ΔRYX.
Considering ΔRST and ΔRYX.
<h3>What is the relation between sides of similar triangles?</h3>The corresponding sides of similar triangles are proportional.
We get ∠RXY=∠RST (Corresponding angles, since XY║ST)
∠RYX=∠RTS (Corresponding angles, since XY║ST)
From AA similarity criteria ΔRST is similar to ΔRYX.
Now, RY/RS = RX/RT = XY/TS.
Therefore, for similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.
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Answer:
x < 3 and x > -1
Step-by-step explanation:
Step 1: Subtract 2 from both sides.
Step 2: Solve absolute value.
Condition 1:
Condition 2:
Therefore, the answer is x < 3 and x > -1.
If all the points have the signs reversed, therefore this means that the whole line is reflected about an axis. Since all are reflected therefore this further means that the new points are still collinear.
We can prove this by plotting the points:
P’(6,2), Q(5,-2), R(4,-6)
<span>From the graph, they are in 1 line hence collinear.</span>
