Answer:
In order to find x, you will have to use the operation of equality to isolate the x.
<em>Now, use the division property of equality and divide by 15 on both sides. This will cancel out the 15 on the left side of the equation and isolate the x completely.</em>
<em>Thus, this is your answer:</em>
Answer:
Step-by-step explanation:
Given:
---
1st problem:
Distribute:
Combine like terms:
---
2nd problem:
Distribute -3 to first factor:
Use foil to simplify:
Replace 
with -1:
Combine like terms:
---
3rd problem:
Distribute 2 to the second factor:
Use foil to simplify:
Replace with -1:
Combine like terms:
----
4th problem:
Distribute:
Combine like terms:
Simplify:
On an isosceles trapezoid, the two sides that are not parallel to each other will be exactly the same length. If this is true, than it would be create a symetric trapezoid. The diagonals would be the same length. The bases of any trapezoid are parallel, so this is true. The diagonals cannot possibly be perpendicular because the 2 nonparallel sides would be slanted. So, the answer is the 3rd choice.
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.
Explanation:
A) The probability that it is brown is the percentage of brown we have. Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%. The probability that one drawn is yellow or blue would be the two percentages added together: 15+20 = 35%. The probability that it is not green would be the percentage of green subtracted from 100: 100-5=95%. Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events. All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.
The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:
0.85^3 = 0.614 = 61.4%.
The probability that at least one is green is computed by subtracting 1-(probability of no green). We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
