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OlgaM077 [116]
2 years ago
13

TConsider △RST and △RYX.

Mathematics
1 answer:
Kryger [21]2 years ago
4 0

For similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.

Given that, for ΔRST, line XY is drawn parallel to side ST within ΔRST to form ΔRYX.

Considering ΔRST and ΔRYX.

<h3>What is the relation between sides of similar triangles?</h3>

The corresponding sides of similar triangles are proportional.

We get ∠RXY=∠RST (Corresponding angles, since XY║ST)

∠RYX=∠RTS (Corresponding angles, since XY║ST)

From AA similarity criteria ΔRST is similar to ΔRYX.

Now, RY/RS = RX/RT = XY/TS.

Therefore, for similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.

To learn more about similar triangles visit:

brainly.com/question/25882965.

#SPJ1

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2 years ago
Martha and sarah leave block p and q towards q and p respectively simultaneously and travel in the same route. After meeting eac
olga_2 [115]

The average speed of Martha and Sarah is 32 km/h.

We need to know about the speed to solve this problem. Speed can be determined as the distance traveled divided by time. It can be written as

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From the question above, we know that:

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