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4 years ago

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Parallel lines in space are coplanar.

1 answer:

kakasveta [241]4 years ago

3 0

Coplanar lines are line witch lie on the same lie on the same plane. two parallel lines or two intersecting lines always lie in a plane. Thus, two line are coplanar, if and only if they are either parallel or intersecting. lines in three dimensional space are coplanar, only if they are not skewed lines.

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Pavel [41]

y=2x+1

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3 years ago

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Nesterboy [21]

Answer:

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Step-by-step explanation:

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anyanavicka [17]

Answer:

Simplified equation in standard form: $y=\frac{1}{4}x^{2}+12\frac{1}{4}$

Original equation in standard form: $y=1/2(x+3)^2+10$

Step-by-step explanation:

$y=\frac{1}{2}(x+3)^2+10$

<u>Step 1: Distribute the </u> $\frac{1}{2}$ <u> :</u>

<u /> $y=(\frac{1}{2}*x+\frac{1}{2}*3)^2+10$ <u />

<u /> $y=(\frac{1}{2}x+1\frac{1}{2})^2+10$ <u />

<u />

<u>Step 2: Take </u> $(\frac{1}{2}x+1\frac{1}{2})$ <u> and square it :</u>

<u /> $y=(\frac{1}{2}x+1\frac{1}{2})^2+10$ <u />

$y=(\frac{1}{2}x)^{2} +(1\frac{1}{2})^2+10$

$y=(\frac{1}{2}x*\frac{1}{2}x)+(1\frac{1}{2}*1\frac{1}{2})+10$

$y=\frac{1}{4}x^{2}+2\frac{1}{4}+10$

<u />

<u>Step 3: Add the constants:</u>

<u /> $y=\frac{1}{4}x^{2}+(2\frac{1}{4}+10)$ <u />

<u /> $y=\frac{1}{4}x^{2}+(12\frac{1}{4})$ <u />

<u />

<u>Step 4: Get rid of the parenthesis:</u>

<u /> $y=\frac{1}{4}x^{2}+12\frac{1}{4}$ <u />

<u />

<u />

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Nutka1998 [239]

Answer:

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Step-by-step explanation:

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