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3 years ago

What is the solution to the equation below? log 20 x^3-2 log x=4

Mathematics

1 answer:

guajiro [1.7K]3 years ago

4 0

20 (4)^3-2
20(64)-2
1280-2
1278

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Read the word problem below.

salantis [7]

Answer:

1 3/5 miles/hr

Step-by-step explanation:

Let C be the speed of the current

Let D be the distance between Chan's house and the park

We know that Distance, D, is = Speed x Time

-----

Chan's speed going upstream is (8 - C)mph.

That gives us:

D = (8-C)(3 hr)

Chan's speed going downstream is (8+C)mph

So we have:

D = (8+C)(2 hr)

We know that the d is the same for these two equations, so:

(8-C)(3 hr) = (8+C)(2 hr)

24 - 3C = 16 + 2C

5C = 8

C = (8/5) or 1 3/5 mph

5 0

2 years ago

Read 2 more answers

Nevaeh invested $660 in an account paying an interest rate of 3% compounded

iris [78.8K]

Answer:

Step-by-step explanation:

Rate 1: 3

%=3+1/4=

\,\,3.25\%\rightarrow 0.0325

3.25%→0.0325

\text{Rate 2: }3\tfrac{1}{8}\%=3+1/8=

Rate 2: 3

%=3+1/8=

\,\,3.125\%\rightarrow 0.03125

3.125%→0.03125

\text{Calculate Final Amount for Nevaeh}

Calculate Final Amount for Nevaeh

\overline{\phantom{\text{Calculate Final Amount for Nevaeh}}}

Calculate Final Amount for Nevaeh

\text{Compounded Continuously:}

Compounded Continuously:

A=Pe^{rt}

A=Pe

P=660\hspace{35px}r=0.0325\hspace{35px}t=14

P=660r=0.0325t=14

Given values

A=660e^{0.0325(14)}

A=660e

0.0325(14)

Plug in

A=660e^{0.455}

A=660e

0.455

Multiply

A=1040.2744

Use calculator (with e button)

\text{Calculate Final Amount for Jonathan}

Calculate Final Amount for Jonathan

\overline{\phantom{\text{Calculate Final Amount for Jonathan}}}

Calculate Final Amount for Jonathan

\text{Compounded Monthly:}

Compounded Monthly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+

)

Compound interest formula

P=660\hspace{35px}r=0.03125\hspace{35px}t=14\hspace{35px}n=12

P=660r=0.03125t=14n=12

Given values

A=660\left(1+\frac{0.03125}{12}\right)^{12(14)}

A=660(1+

0.03125

)

12(14)

Plug in values

A=660(1.0026042)^{168}

A=660(1.0026042)

168

Simplify

A=1021.6468

Use calculator

\text{How much more money Nevaeh has:}

How much more money Nevaeh has:

1040.2744-1021.6468

1040.2744−1021.6468

18.6276

\$ 19

$19

4 0

2 years ago

An airplane flies 315 km in 1 hour 45 minutes. Calculate the average speed.

valentina_108 [34]

Answer:

3 km per minute

Step-by-step explanation:

speed = distance / time

315km/105 minutes

= 3 km per minute

4 0

2 years ago

One number is 5 times another number.their sum is 90.find the numbers.

alexgriva [62]

Step-by-step explanation:

let both unknowns be x and y

x = 5y. ......(1)

x + y = 90. ......(2)

sub eqn (1) into eqn (2)

5y + y = 90

6y = 90

y = 90/6

= 15

sub y = 15 to eqn (1)

x = 5y

x = 5 × 15

× = 75

4 0

2 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago