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fenix001 [56]
3 years ago
13

99 point please help

Mathematics
2 answers:
masya89 [10]3 years ago
6 0

For the first line its y=.5x-3

and for the second line its y= 3x +3

____ [38]3 years ago
4 0
It wants it to be in slope-intercept form.

y=mx+b

We have to first find the slope and plug it into point-slope form.

y-y1=m(x-x1)

Find the slope of the second line. (I did this one first on accident)

Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)

y-3=3(x-0)
y-3=3x

Add 3 to the other side.

y= 3x +3 <- <em>for the second line</em><em>
</em>
Now, the second.

rise/run= 1/2= .5 Use point (6,0)

y-0=.5(x-6)
y= .5x-3 

y=.5x-3 <- for the first line

I hope this helps!
~kaiker




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