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2 years ago

Solve the inequality and the graph the solution

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

7 0

Answer: C. x is less than or equal to 2

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5/9 x 2/6 in simplest form please answer asap

Damm [24]

The answer would be 5/27
(If you want me to explain I can)

Hope this helps

Have a great day/night

8 0

3 years ago

How many three-fourths are in 3?

hodyreva [135]

There are four 3/4 in 3.

6 0

3 years ago

Read 2 more answers

Hi please help me the pic is up there

mojhsa [17]

Answer:

4p^3 (4p + 1)

Step-by-step explanation:

All we can do with this equation is factor it.

16p^4 + 4p^3

When we look at the coefficients, there is a common factor of 4 with 16 and 4. The p's are also common factors, and we can take out a common factor of x^3. We can combine these common factors and take them out of the equation at the same time.

4p^3 (4p + 1)

8 0

2 years ago

which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

6 0

3 years ago

A certain radioactive material decays in such a way that the mass in kilograms remaining after t years is given by the function

Angelina_Jolie [31]

The mass of radioactive material remaining after 50 years would be 48.79 kilograms

<h3>How to determine the amount</h3>

It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.

Given the radioactive decay formula as

m(t)=120e−0.018t

Where

t= 50 years

m(t) is the remaining amount

Substitute the value of t

$m(t) = 120e^-^0^.^0^1^8^(^5^0^)$

$m(t) = 120e^-^0^.^9$

Find the exponential value

m(t) = 48.788399

m(t) = 48.79 kilograms to 2 decimal places

Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms

Learn more about half-life here:

brainly.com/question/26148784

#SPJ1

7 0

2 years ago