If n is the first integer, then n+2 is the second one. The equation for the sum can be written as
n + (n+2) = 24 . . . . . . this equation can be used to solve the problem
2n = 22 . . . . . . . . . . . simplify, subtract 2
n = 11
The integers are 11 and 13.
_____
I like to solve problems like this by looking at the average of the integers. Here, it is 24/2 = 12. The consecutive odd integers whose average is 12 are 11 and 13.
Answer:
Step-by-step explanation:
Sample data
204.999 206.149 202.102 207.048 203.496 206.343 203.496 206.676 205.831
N=9
Sum, Σx: 1846.14
Mean, μ: 205.12666666667
Variance, s^2: 2.6217475555555
Std dev = s = 1.619
The sample mean follows a t distribtion with df =8
Mean difference = 205.13-204.8 = 0.50
Std error = std dev/sqrt n = 0.540
Test statistic = Mean diff/se = 0.9259
p value = 0.1907 (one tailed at 95%)
Since p >0.05 we accept null hypothesis.
We cannot conclude that the mean shade of Mezza Perla tile (µ) is greater than 204.8
True. A relation just pairs two sets. An object in the first set can relate to more than one in the second.
The 9 would be in the 10s place so the 9 is 0.9/10
Solution: x = 4
Here’s a more clear explanation I found :)) have a good day
