Answer:
1/2
Explanation:
Genotype of the heterozygous mother= X^cX
Genotype of color-blind father= X^cY
A cross between heterozygous mother and color blind father would give progeny in following phenotype ratio=
1 colorblind daughter: 1 colorblind son: 1 carrier but normal daughter: 1 normal son.
Therefore, this couple has 1/2 probability of getting a colorblind daughter is 1/2
