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Sergeeva-Olga [200]
3 years ago
11

How do you do this I'm confused?

Mathematics
1 answer:
amm18123 years ago
5 0
1st arrange the data points from smaller to larger:

32  35  38  40  42  46  48 | 48  50  51  52  53  54  55  56
                    |                    |
                    |              Median( 48+48)/2 = 48
          1st Quartile
               = 40


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Anvisha [2.4K]
22.5 cm because 6 divided by 1.2 = 5 so 5 x 4.5 = 22.5
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Answer:

Exact form : x=6/5

Decimal form : x=1.2

Mixed Number form : x=1 1/5

Step-by-step explanation: Solve for x by simplifying both sides of he equation, then isolating the variable.

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4 0
3 years ago
Can someone pls help out
weqwewe [10]

Answer:

A. 99.87%

Step-by-step explanation:

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6 0
3 years ago
Find the domain of the function (f/g)(x) given f (x)=x^2-4x-5 and g(x)=x^2-25
stealth61 [152]

Answer:

all real numbers except ±5.

Step-by-step explanation:

Each function (f(x), g(x)) has a domain that is all real numbers. Their quotient (f(x)/g(x)) must exclude values that make g(x) = 0. The quotient is undefined when the denominator is zero. Those excluded values are x = ±5.

The domain of (f/g)(x) is all real numbers except ±5.

___

Of course you recognize x^2 -25 = 0 has solutions x = ±√25 = ±5. You can get there two ways:

  1. add 25 and take the square root: x^2=25; x=±√25.
  2. factor the difference of squares and set the factors to zero: (x-5)(x+5)=0 has solutions x-5=0 and x+5=0, that is, x = ±5.
5 0
3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
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