What form of math is this?
Width of the rectangle is 9 units
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units
Area of the rectangle = length × width
54 = x (x - 3)
54 = x² - 3x
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)
x(x + 6) - 9(x + 6) = 0
(x + 6)(x - 9) = 0
x = -6, 9 (negative value is neglected)
x = 9 units
Answer:
Females = 17 and males = 23
Step-by-step explanation:
Given that,
Total no of students in the class = 40
Let no. of females = x
No. of males = 6+x
ATQ,
Total students = males + females
40 = x+6+x
40-6 = 2x
34 = 2x
x = 17
Hence, there are 17 females and (6+17= 23) males.
Answer:
109.5; B
Step-by-step explanation:
From your identity,
CosA = adjacent/ hypothenus
A represent an arbitrary angle between the sides in question.
In the question above, A=64
Hypothenus is the longest side and adjacent is the side just below the angle .
In the above case,
Hypothenus= X
adjacent =48
This means;
Cos64 = 48 /X
X = 48 / cos64; [ from cross multiplication and diving through by cos64]
X = 48 /0.4383 [ cos64 in radian = 0.4383]
= 109.51
= 109.5 to the nearest tenth.
Note( do your calculation of angle in radian or else, you won't get the answer)
Answer:
2 ;-;
Step-by-step explanation:
