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erma4kov [3.2K]
3 years ago
8

Find the mean, median, mode, and range of the data: {17, 2, 16, 3, 13,5,7,8,9, 11, 5, 2, 1,20}

Mathematics
2 answers:
Luba_88 [7]3 years ago
6 0

Answer:

median:8 mean:199 that is all i know i might be wrong

Step-by-step explanation:

erastovalidia [21]3 years ago
5 0
Mean: 8.5
Find the average:

17+2+16 +3+13+5+7+8+9+11+5+2+1+20=119

119/14=8.5

Median: 7.5
Find the middle number:
17, 2, 16, 3, 13, 5, 7, 8, 9, 11, 5, 2, 1, 20

Put them in order (smallest to biggest):
1, 2, 2, 3, 5, 5, 7, 8, 9, 11, 13, 16, 17, 20

Find middle number(s):
7, 8.. In this situation sense there are two middle numbers, find the average of the two:
7+8=15, 15/2=7.5

Mode: 2,5
Find the most common occurring number (there can be more than one):
2 and 5 appear the most

Hope this helps!!


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Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

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p_1=X_1/n_1=494/1000=0.494

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

p_2=X_2/n_2=552/1000=0.552

The difference between proportions is (p1-p2)=-0.058.

p_d=p_1-p_2=0.494-0.552=-0.058

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022

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MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

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