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Orlov [11]
3 years ago
15

How do I reflect this over y=1?

Mathematics
2 answers:
7nadin3 [17]3 years ago
6 0
Check the picture below.

Semenov [28]3 years ago
5 0
The orange is the original and the blue is the reflection over y=1
 

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Anonymous 3 years ago
amm1812
Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.

Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.

From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH

Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees

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Thus, mHFG + mACB = mHFG + mDFH

Therefore, mACB = mDFH.
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