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Orlov [11]
3 years ago
15

How do I reflect this over y=1?

Mathematics
2 answers:
7nadin3 [17]3 years ago
6 0
Check the picture below.

Semenov [28]3 years ago
5 0
The orange is the original and the blue is the reflection over y=1
 

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Whats the answer to 45=x(14-x)
ElenaW [278]
45=x(14-x)\\ \\45=14x-x^2\\ \\x^2-14x+45=0\\ \\\Delta = b^{2}-4ac =  (-14)^{2}-4*1* 45=196-180=16 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{14- \sqrt{16}}{2}=\frac{14-4}{2}= \frac{12}{2}=6\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{14+\sqrt{16}}{2}=\frac{14+4}{2}= \frac{18}{2}=9
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Solve pls brainliest
sashaice [31]

Answer:

w = 2/7

Step-by-step explanation:

You do 8 divided by 4 over 7, which is 2/7.

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2 years ago
What type of mathematical law is this (6+4)+100=6+(4+100)​
dusya [7]
Search the property of addition
8 0
3 years ago
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solve each problem.simplify your answer.One inch on a map equals 375 miles.what do 5 3/4 inches represent.
larisa [96]
1 inch × 375 = 375 miles
5³/₄ inches × 375 = 2156¹/₄ miles

If an inch on a map is equal to 375 miles, then 5³/₄ inches on an map is equal to 2156¹/₄ miles.
3 0
2 years ago
12.what is the probability that a boy and a girl chosen randsomly will be seniors?
zhenek [66]

\frac{\textbf{1}}{\textbf{20}}

Step-by-step explanation:

Probability=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}

Probability for a randomly chosen girl to be senior=\frac{\text{number of senior girls}}{\text{total number of girls}}

Probability for a randomly chosen girl to be senior=\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}

Probability for a randomly chosen boy to be senior=\frac{\text{number of senior boys}}{\text{total number of boys}}

Probability for a randomly chosen girl to be senior=\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}

For two independent events,

Probability for both event 1 and event 2 to take place=\text{probability of event 1} \times \text{probability of event 2}

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior=\text{probability for boy to be senior}\times\text{probability for girl to be senior}

Probability for both boy and girl chosen to be senior=\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}

So,required probability is \frac{1}{20}

3 0
3 years ago
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