Question

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Answer 1

Using quadratic function concepts, it is found that:

a) The equation is: 16t² - 64 = 0.

b) It takes 4 seconds before the weight is caught by the net.

What is the quadratic equation for a projectile's height?

It is given by:

h(t) = -16t^2 + v(0)t + h(0).

In which:

• v(0) is the initial velocity.

• h(0) is the initial height.

Item a:

In this problem, the object starts from rest at a height of 67 ft, hence v(0) = 0 and h(0) = 67.

Then, the equation for the height is given by:

h(t) = -16t^2 + v(0)t + h(0)

h(t) = -16t^2 + 67

It hits the net when h(t) = 3, hence:

3 = -16t^2 + 67

16t² - 64 = 0.

Item b:

16t² = 64

$t = \pm \sqrt{4}$

t = 4, as time is positive.

It takes 4 seconds before the weight is caught by the net.

More can be learned about quadratic function concepts at brainly.com/question/24737967