1 answer:
Using quadratic function concepts, it is found that:
a) The equation is: 16t² - 64 = 0.
b) It takes 4 seconds before the weight is caught by the net.
<h3>What is the quadratic equation for a projectile's height?</h3>It is given by:
h(t) = -16t^2 + v(0)t + h(0).
In which:
- v(0) is the initial velocity.
- h(0) is the initial height.
Item a:
In this problem, the object starts from rest at a height of 67 ft, hence v(0) = 0 and h(0) = 67.
Then, the equation for the height is given by:
h(t) = -16t^2 + v(0)t + h(0)
h(t) = -16t^2 + 67
It hits the net when h(t) = 3, hence:
3 = -16t^2 + 67
16t² - 64 = 0.
Item b:
16t² = 64
t = 4, as time is positive.
It takes 4 seconds before the weight is caught by the net.
More can be learned about quadratic function concepts at brainly.com/question/24737967
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Diagram? There is no diagram given.
a.
Cannot solve b without the diagram.
Answer:
and
are parallel.
is neither parallel nor perpendicular.
Step-by-step explanation:
First, you have to simplify each equation in terms of y.
Your first equation is already in terms of x, so simplify your second equation.
Now you can simplify your third equation.
These are your three equations in terms of y:
Now, all you have to know is how to tell using your slope if a line is parallel or perpendicular to another.
Two parallel lines will have the exact same slope.
Two perpendicular lines will have slopes which are opposite reciprocals. For example, a line with a slope of 2 is perpendicular to a line with a slope of , as they have opposite signs and are reciprocal (2/1 versus 1/2) to each other.
Your first two equations have the same slope and are therefore parallel.
Your third equation is a reciprocal, but it is not opposite, and is therefore not parallel nor perpendicular.