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wolverine [178]
3 years ago
7

Please help!!!!! Its timed !!!!! Ill give out most brainly and extra points !!!

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0
BRAINLY BRAINLY BRAINLY the answer is C
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What is the bisector of RS
Inessa05 [86]

Step-by-step explanation: A line, ray, or line segment (referred to as segment) that is perpendicular to a given segment at its midpoint is called a perpendicular bisector. ... In the diagram above, RS is the perpendicular bisector of PQ, since RS is perpendicular to PQ and PS≅QS. Additionally, since PS≅QS, point S is the midpoint of PQ.

8 0
2 years ago
The list shows the numbers of each type of pie baked at a bakery today.
Alenkasestr [34]
35%, because the apple pies account for 65% of the pies made
4 0
3 years ago
the students at Woodward elementary voted for a schools mascot the falcon won with 5/8 and the eagle came in second with 1/3 of
Stella [2.4K]

One third written as a fraction is 1/3. You can also write it as a decimal by simply dividing 1 by 3 which is 0.33.

If you multiply 0.33 with 536 you will see that you will end up with the same answer as above.

You may also find it useful to know that if you multiply 0.33 with 100 you get 33.33. Which means that our answer of 178.67 is 33.33 percent of 536.

Solution : 178.67

4 0
3 years ago
Simplify this please​
Drupady [299]

Answer:

1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. A rocket is launched from atop a
umka2103 [35]
When it hits the ground, then h=0
find the xintercept or in this case the tintercepts
c=76
v=135

h=-16t^2+135t+76
use quadratic formula

ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

a=-16
b=135
c=76

x=\frac{-135+/- \sqrt{135^2-4(-16)(76)} }{2(-16)}
x=\frac{-135+/- \sqrt{18225+4864} }{-32}
x=\frac{-135+/- \sqrt{23089} }{-32}
aprox
x=-0.5297 or 8.967
exclude the negative root since you can't have negative time

means that it takes 8.97 seconds to hit the ground


4 0
3 years ago
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