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earnstyle [38]
3 years ago
12

Describe how (2^3)(2^-4) can be simplified.

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
5 0

Answer:

2^ (-1)

1/2

Step-by-step explanation:

Add the exponents which have common bases.

3 + (-4) = -1

2^ (-1)

1 / 2

Please mark for Brainliest!! :D Thanks!!

For more information, please comment below and I'll respond ASAP!

lukranit [14]3 years ago
3 0

Answer:

The simplified form of the provided expression is 2^{-1}\ or\ \frac{1}{2}

Step-by-step explanation:

Consider the provided expression:

(2^3)(2^{-4})

Use the product rule of exponent:

a^m \cdot a^n=a^{m+n}

Now use the above formula to simplify the provided expression.

(2^3)(2^{-4})=2^{3+(-4)}

(2^3)(2^{-4})=2^{3-4}

(2^3)(2^{-4})=2^{-1}

Hence, the simplified form of the provided expression is 2^{-1}\ or\ \frac{1}{2}

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Tpy6a [65]

Answer:

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Step-by-step explanation:

4 0
3 years ago
(cosxtanx-tanx+2cosx-2)/tanx+2=cosx-1<br> can someone show me how to prove this?
uysha [10]

Answer:

See detail below.

Step-by-step explanation:

A word of caution before getting to the actual problem: I believe there is an important set of brackets missing in the original post. The expression on the left hand side should be:

(cosxtanx-tanx+2cosx-2)/(tanx+2)

Without the brackets, it is left unclear whether the denominator is just tanx or tanx+2. I recommend to use brackets wherever any doubt could arise.

Now to the actual problem: \we can make the following transformations on the left hand side:

\frac{\cos x \tan x + 2\cos x -2}{\tan x +2}=\frac{\cos x \frac{\sin x}{\cos x}  + 2\cos x -2}{\frac{\sin x +2\sin x}{\cos x} }=\\=\frac{\cos x \sin x - \sin x + 2\cos^2 x - 2\cos x}{\sin x + 2\cos x}=\\=\frac{\cos x \sin x +2\cos^2 x }{\sin x + 2\cos x}-1=\\=\cos x -1

which is shown to be the same as the right hand side, which was to be shown.

7 0
3 years ago
Practice another write the function in terms of unit step functions. find the laplace transform of the given function. f(t) = t,
balu736 [363]

Using the Laplace transform to solve the given integral equation  f(t) = t, 0 ≤ t < 4 0, t ≥ 4 is \frac{4(1-2e^-5s)/}{s}

explanation is given in the image below:

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7 0
2 years ago
How do you solve surface area
LekaFEV [45]
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Most other shapes, whether 3-dimensional or 2-dimensional, can be calculated by simply adding together the areas of their component parts.  An octagon can be divided into 8 isosceles triangles, which if you're given the right information are easy to calculate for (height times base divided by 2).  Once you find the area of one piece of the octagon, multiply by 8 (the number of sides).  This works for any regular polygon of n sides.
 
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5 0
3 years ago
Caroline and Sarah in some money and share it in the ratio 2:1. Caroline gets £45 more than
12345 [234]

Answer:

£22.5

Step-by-step explanation:

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Which would give us the answer 45:22.5

Sarah got £22.5

8 0
3 years ago
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