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3 years ago

What is the value of F(5) in the function below? F(x) = 3^x

Mathematics

2 answers:

Wewaii [24]3 years ago

8 0

The answer is 243. F(5)= 3^5= 3*3*3*3*3= 243

boyakko [2]3 years ago

3 0

Answer: The required value of F(5) is 243.

Step-by-step explanation: We are given the following function F(x) :

$F(x)=3^x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of F(5).

To find the required value, we need to substitute x = 5 in equation (i).

So, from (i), we get

$F(5)=3^5=3\times3\times3\times3\times3=243.$

Thus, the required value of F(5) is 243.

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3 years ago

5×67-34÷2+5 equals what

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Answer: $323$

Step-by-step explanation:

1) Add () to the equation: $(5*67)-(34/2)+5$

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4) Subtract: $335-17=318$

5) Add: $318+5=323$

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3 years ago

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Sophie Ruth is eating a 50-gram chocolate bar that contains 30%, cocoa. How many grams of cocoa is in the chocolate bar?

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We need to multiply the percentage as a decimal (0.30) with the amount of chocolate (50 g):

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2 years ago

Choose the operation you need to perform first 3 + 5 x 8 ÷ 2

serious [3.7K]

Answer:

Multiplication

Step-by-step explanation:

First multiplication 5x8=40 divided by 2 = 20 add back the three so the equation is now 20+3 =23 The final answer

Go by the order PEMDAS

P-Peretnahesis-there is none so skip this step

E-Exponents-There is none so skip this step

M-Multiplication-and division are mixed so whichever one comes first you do and then do the multiplication and division operations in the order they go

D-Division & multiplication are mixed so whichever one comes first you do and then do the multiplication and division operations in the order they go.

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1 year ago

Read 2 more answers

A red die and a blue die are rolled. You win or lose money depending on the sum of the values of the two dice. If the sum is 6 o

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Answer:

The expected value of X is $0.0833.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

For each dice, there are 6 possible outcomes(values from 1 to 6). So for 2 dices, there are $6^2 = 36$ desired outcomes.

Desired outcomes:

Sum 5: (1,4), (2,3), (3,2), (4,1).

Sum 6: (1,5),(2,4),(3,3),(4,2),(5,1)

Sum of 9: (3,6), (4,5), (5,4), (6,3)

Sum of 10: (4,6), (5,5), (6,4)

Sum of 12: (6,6)

Probabilities:

5 + 3 = 8 outcomes in which the sum is 6 or 10, that is, 8/36 probability of winning $4.

4 + 4 + 1 = 9 outcomes in which the 5, 9, or 12, that is, 9/36 probability of winning $1.

36 - (8 + 9) = 36 - 17 = 19 remaining outcomes, that is, 19/36 probability of losing $2.

What is the expected value of X?

Multiplication of each outcome by its probability. So

$E(X) = \frac{8}{36}*4 + \frac{9}{36}*1 - \frac{19}{36}*2 = \frac{8*4 + 9*1 - 19*2}{36} = \frac{32 + 9 - 38}{36} = \frac{3}{36} = 0.0833$

The expected value of X is $0.0833.

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3 years ago