Answer:
The answer is just 4
Step-by-step explanation:
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Answer:
(1 ) Inner curved surface area of the well is 109.9 sq. meters.
(2) The cost of plastering the total curved surface area is 4396.
Step-by-step explanation:
The inner diameter = 3.5 m
Depth of the well = 10 m
Now, Diameter = 2 x Radius
⇒R = D/ 2 = 3.5/2 = 1.75
or, the inner radius of the well = 1.75 m
CURVED SURFACE AREA of cylinder = 2πr h
⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)
= 109 sq. meters
Hence, the inner curved surface area of the well is 109.9 sq. meters.
Now, the cost of plastering the curved area is 40 per sq meters
So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)
= 109.9 x (40)
= 4396
Hence, the cost of plastering the total curved surface area is 4396.
Answer:
-x^8+10x^3-7x^2+7x+15
Step-by-step explanation:
-7x+10x^3-7x^2-x^8+15
Standard form is from highest power to lowest power of x
-x^8+10x^3-7x^2+7x+15
Answer:
9
Step-by-step explanation:
She's Gonna Run 6 more again and half of 6 is 3 so 9 because she's running the same amount and adding half of it
1/ 816
Step-by-step explanation:
Step 1 :
Given
Total number of students in the school = 18
Number of students randomly selected = 3
Step 2 :
Number of ways in which 3 students can be selected out of 18 students is
C(18,3) = 18! /(3!(*18-3)!) = 18*17*16/3*2*1 = 816
Number of ways in which 3 students are selected and they are the youngest = 1
Hence the probability of selecting 3 youngest students from the available students is 1/ C(18,3) = 1/ 816