The first one would be 12/50 and I’m not sure about the second one
I believe it's 36. The vertices have the same x coordinate so I found the difference between the y coordinates.
The triangle has a 45-deg angle.
The base angles are congruent and measure 67.5 deg.
The congruent sides measure 1 ft.
Use law of sines to find the length of the base.
![\dfrac{\sin 67.5^\circ}{1~ft} = \dfrac{\sin 45^\circ}{b}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B%5Csin%2067.5%5E%5Ccirc%7D%7B1~ft%7D%20%3D%20%5Cdfrac%7B%5Csin%2045%5E%5Ccirc%7D%7Bb%7D%20)
![b = \dfrac{\sin 45^\circ}{\sin 67.5^\circ}~ft](https://tex.z-dn.net/?f=%20b%20%3D%20%5Cdfrac%7B%5Csin%2045%5E%5Ccirc%7D%7B%5Csin%2067.5%5E%5Ccirc%7D~ft%20)
![b = 0.765~ft](https://tex.z-dn.net/?f=%20b%20%3D%200.765~ft%20)
Draw a height from the vertex of the 45-deg angle to the base.
Half of the base is 0.765 ft/2 = 0.383 ft
We can find the height of the triangle using the small triangles.
0.383^2 + h^2 = 1^2
h = 0.9239 ft
A = bh/2 = 0.765 * 0.9239/2 ft^2
A = 0.354 ft^2