Answer:
39.2°
Step-by-step explanation:
Vertical angles are always congruent.
Answer:
B)
Step-by-step explanation:
- Rational number: can be expressed as a ratio of two integers
- Irrational number: cannot be expressed as a ratio of two integers



18 - 2H = 12 - .5H
Combine the variables
18 - 2H + .5H = 12 - .5H + .5H
18 - 1.5H = 12
Combine the whole numbers
18 - 18 - 1.5H = 12 - 18
-1.5H = -6
Divide by -1.5
-1.5H/-1.5 = -6 / -1.5
H = 4
The answer is 4 hours
Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.