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vazorg [7]
4 years ago
13

For a school art project, Kali has 604 square tiles measuring 1 inch on each side. She plans to use the tiles to completely cove

r the box in the shape of a rectangular prism shown below. (FORMULA: Surface Area = 2lw + 2lh + 2wh) Which statement about Kali's tiles is true? Group of answer choices Kali needs 476 more tiles to completely cover the box. Kali needs 104 more tiles to completely cover the box. Kali will have 534 tiles left after completely covering the box. Kali will have 250 tiles left after comp

Mathematics
1 answer:
Crazy boy [7]4 years ago
4 0

Answer:

Kali needs 104 more tiles to completely cover the box.

Step-by-step explanation:

Length of box =  20 in

Breadth of box = 6 in

Height of box= 9 in

Total surface area of box = 2lw + 2lh + 2wh

Total surface area of box = 2(20)(6) + 2(20)(9) + 2(6)(9)

Total surface area of box = 708 sq. in.

Side of tile = 1 in

Area of 1 tile = Side^2 = 1^2 = 1 sq. in

Area of 604 tiles = 604 sq. in.

Area remain uncovered = 708 - 604 = 104 sq.in.

So, Kali needs 104 more tiles to completely cover the box.

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21 Maria sold small boxes of candy for $1 and
Anna35 [415]

Answer:

There where 10 <u>more</u> Small boxes sold than Large boxes.

Step-by-step explanation:

<u>This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable. </u>

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable y and an Independent variable x. In a system of Two Linear equations we have<u> two equations</u> of the same variable sets (thus Two Independent variables) so in this case both y and x will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

<u>Given Information:</u>

  • Small Boxes (lets call them s) cost $1 per box
  • Large Boxes (lets call them l) cost $4 per box
  • Total Number of Boxes sold is 30
  • Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

s+l=30        Eqn(1): Total Number of Boxes

1s+4l=60     Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, s and l respectively.

From Eqn(1) we see that

s=30-l      Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for l as:

1(30-l)+4l=60

30-l+4l=60       Factored out bracket

3l=60-30          Gather similar terms on each side and simplify

3l=30

l=\frac{30}{3}

l=10

Plugging in the value for l=10 in Eqn(3) we have

s=30-10\\s=20

So we know that they were<u> 10 Large Boxes and 20 Small Boxes sold</u>, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

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4 years ago
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