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lana66690 [7]
3 years ago
15

A triangle height is 2/4 mm and the base is 8 mm. What is the area of the triangle?

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer:

the answer would be 2mm^2

krok68 [10]3 years ago
3 0

Answer:

2

Step-by-step explanation:

Triangle Area Formula: (b*h)/2

B: 8

H: 2/4= 1/2=0.4

8*0.5/2= 2

Area ofthe triangle= 2

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Explain how knowing that 5/8 = 0.625 helps you write the decimal for 4 5/8
tatyana61 [14]
When writing a decimal, the numbers to the left of the decimal are whole numbers greater then or equal to 1. The numbers to the right of the decimal are numbers less then 1.

if u know 5/8 = 0.625, then 4 5/8 = 4.625
4 0
3 years ago
Variable termes X-12-3X+22
adell [148]

Answer: x + 12 = 3x + -22

12 + x = 3x + -22

Reorder the terms:

12 + x = -22 + 3x

Solving

12 + x = -22 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

12 + x + -3x = -22 + 3x + -3x

Combine like terms: x + -3x = -2x

12 + -2x = -22 + 3x + -3x

Combine like terms: 3x + -3x = 0

12 + -2x = -22 + 0

12 + -2x = -22

Add '-12' to each side of the equation.

12 + -12 + -2x = -22 + -12

Combine like terms: 12 + -12 = 0

0 + -2x = -22 + -12

-2x = -22 + -12

Combine like terms: -22 + -12 = -34

-2x = -34

Divide each side by '-2'.

x = 17

Simplifying

x = 17

7 0
3 years ago
I trying to reduce But I don't know how can someone help me please thanks!
meriva
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3 0
3 years ago
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Suppose the number 1155 is written as the product of three positive integers. What is the smallest possible value of the sum of
ipn [44]
3. the equation I used is: 3×5×77
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3 years ago
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Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"
dsp73
For any scalars c_1,c_2, we have

c_1\mathbf v\times c_2\mathbf w=c_1c_2\mathbf v\times\mathbf w

So

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\mathbf v\times\mathbf w

We have

\mathbf v\times\mathbf w=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\-2&12&-3\\-7&4&-6\end{vmatrix}
=\begin{vmatrix}12&-3\\4&-6\end{vmatrix}\mathbf i-\begin{vmatrix}-2&-3\\-7&-6\end{vmatrix}\mathbf j+\begin{vmatrix}-2&12\\-7&4\end{vmatrix}\mathbf k
=-60\,\mathbf i-(-9)\,\mathbf j+76\,\mathbf k
=\begin{bmatrix}-60\\9\\76\end{bmatrix}

which makes

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}
4 0
3 years ago
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