2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
Answer:
Step-by-step explanation:
Given
Solving (a): NK
MK is a diagonal and NK is half of the diagonal. So:
Solving (b): JL
JL is a diagonal, and it is twice of NL.
Solving (c): KL
To solve for KL, we consider triangle KNL where:
and
Solving (d - h):
To do this, we consider triangle JKN
-- diagonals bisect one another at right angle
Alternate interior angles are equal. So:
Similarly:
So:
250
1250 & 250 divided by 1250
54x89=4806
123x85=10,455
64x15=960
264x14=3,696
Answer:
x=40
Step-by-step explanation:
Because every triangle's angles add up to 180 degrees, you know 3x+x+20=180. Since 3x and x are like terms, you can add them to get 4x. 20 and 180 are also like terms. However, to move your 20 to the side of 180, you need to subtract it. So you have 4x=160. To get x by itself, you divide 4x and 160 by 4. 4x/4 is x, and 160/4 is 40. So your answer is x=40.
