Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
#SPJ1
Answer:
D= 19
Step-by-step explanation:
114 ÷ 6 is 19
You take 69 * 0.35 and then take that total (24.15) so 60-24.15= 35.85 then to find the tax take 35.85*.07=2.51 so your answer is 35.85+2.51=38.36
Answer:
123
Step-by-step explanation:
BODMAS
1.multiply 20 by 2
2.20 ×2
3. 40+22+40+20+43=123