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2 years ago

7

Whats the answer to m=10x-x

1 answer:

Dennis_Churaev [7]2 years ago

7 0

Answer:

9x

Step-by-step explanation:

m=10x-x

10x means x in ten places so, it can be subtracted normally

m=9x

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A store sells cantaloupes at a price of 6 for $9.00. Henry decides he does not have enough money to buy 24 cantaloupes. He can b

irina [24]

Answer:

$22.50

Step-by-step explanation:

First you have to add up $9.00 + $9.00 because it's 6 for $9.00 which is $18 and now you have 12 cantaloupes but since you need 15 you now divide 6 by 9.00 which gives you $1.50 which is the origanl price the cantaloupes were before and now you find the price of 3 cantaloupes 3x$1.50 = $4.50 now you add $18 + 4.50 = $22.50 :)

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2 years ago

Two functions, A and B, are described as follows: Function A y = 8x + 3 Function B The slope is 1 and the y-intercept is 4. How

____ [38]

1. Subtract 3 from both sides:
y - 3 = 8x
2. Divide both sides by 8:
y - 3/8 = x
3. Switch sides:
x = y - 3/8

8 0

2 years ago

Answer each question with a fraction.

otez555 [7]

Answer:

The average speed is $\frac{3}{35}\frac{ft}{min}$

Step-by-step explanation:

we know that

To find out the average speed divide the distance by the time

Let

s -----> average speed

d -----> the distance in feet

t ----> the time in minutes

$s=\frac{d}{t}$

we have

$d=6\ ft$

$t=70\ min$

substitute

$s=\frac{6}{70}\frac{ft}{min}$

Simplify

$s=\frac{3}{35}\frac{ft}{min}$

5 0

3 years ago

What are the coordinates for the function of the vertex for the quadratic function below

lakkis [162]

We will need to picture for this.

8 0

2 years ago

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript one-fourth x?

Nat2105 [25]

<h3>Answer: Choice C</h3>

RootIndex 12 StartRoot 8 EndRoot Superscript x

12th root of 8^x = (12th root of 8)^x

$\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}$

=========================================

Explanation:

The general rule is

$\sqrt[n]{x} = x^{1/n}$

so any nth root is the same as having a fractional exponent 1/n.

Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)

$\sqrt[3]{8} = 8^{1/3}$

-----

Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so

(1/3)*(1/4)x = (1/12)x

In other words,

$\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/3)*(1/4)x}$

$\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/12)x}$

-----

From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this

$8^{(1/12)x} = \sqrt[12]{8^{x}}$

$8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}$

4 0

2 years ago

Read 2 more answers