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faust18 [17]
3 years ago
8

At Priscilla's Purse Warehouse, it takes fraction 2 over 3 of a day to complete fraction 1 over 9 of an order of purses. At this

rate, how long will it take to complete the entire order of purses?
Mathematics
1 answer:
kherson [118]3 years ago
6 0
(2/3) / (1/9) = x / 1....2/3 day to 1/9 order = x days to 1 order
cross multiply
(1/9)(x) = (2/3)(1)
1/9x = 2/3
x = 2/3 * 9
x = 18/3
x = 6 days <==
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The product is 10730 is the ñame
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Which steps will verify that a parallelogram is a rectangle? Check all that apply.
avanturin [10]

Answer;

-Calculate the lengths of the diagonals, and show that they are equal.

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Explanation;

-A parallelogram is a quadrilateral with 2 pairs of opposite, equal and parallel sides. If the diagonals of a parallelogram are congruent, then it’s a rectangle and also if a parallelogram contains a right angle, then it’s a rectangle.

8 0
3 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
Drag and drop an answer to each box to correctly complete the explanation for deriving the formula for the volume of a sphere
denis-greek [22]

The answers that would fill in the blanks are

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<h3>What is the Cavalier's principle?</h3>

This principle states that if two solids are of equal altitude then the sections that the planes would make would have to be parallel and also be at the same distances from their bases which are equal such that the volumes of the solids would be equal.

Now we have to fill in the blanks with the solution.

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius r and height<u> 2r</u> minus the volume of two cones, each with a radius and height of r. A cross section of the sphere is a <u>circle</u> base of cylinder, is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is an <u>annulus_ </u>.The volume of the cylinder with radius r and height 2r is 2πr³, and the volume of each cone with radius r and height r is 1/3πr³. So the volume of the cylinder minus the two cones is 4/3πr³. Therefore, the volume of the sphere is by Cavalieri's principle

Read more on Cavalieri's principle here

brainly.com/question/22431955

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5 0
8 months ago
Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)
TEA [102]

Answer:

<h2>a. \:  {x}^{2}  + 2</h2>

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solution,

a. \: x(x + 2) \\  \:  \:  = x \times x + 2 \times x \\  \:  \:  =  {x}^{2}  + 2x

b . \: x(2x - 5) \\  \:  = x \times 2x - x \times 5 \\  \:  \:  = 2 {x}^{2}  - 5x

c. \: 2x(3x + 4) \\  \:  = 2x \times 3x + 2x \times 4 \\  \:  \:  = 6 {x}^{2}  + 8x

d. \: 6x(x - 2) \\  \:  \:  = 6x \times x  - 6x \times 2 \\  \:  \:  = 6 {x}^{2}  - 12x

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0
2 years ago
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