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3 years ago

40x=10x^2+41 Identify the number of solutions and their types using the discriminant

Mathematics

1 answer:

nydimaria [60]3 years ago

6 0

Number of solutions: no roots

Type of solution: Not Real

Step-by-step explanation:

We need to identify the number of solutions and their types using the discriminant.

We are given: $40x=10x^2+41\\$

Rearranging:

$40x-10x^2-41=0\\10x^2-40x+41=0$

Discriminant can be found by: $b^2-4ac$

where b=-40, a=10 and c=41

Putting values:

$b^2-4ac\\=(-40)^2-4(10)(41)\\=1600-1640\\=-40\\$

So, Discriminant is -40

If the discriminant is less than zero i.e -40 then there are no real roots.

So, Number of solutions: no roots

Type of solution: Not Real

Keywords: discriminant

Learn more about discriminant at:

#learnwithBrainly

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(45pts) An elevator holds at most 1,400 pounds. A team of movers and their cart have a combined weight of 1,200 pounds. If each

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Let $x$ be the number of boxes the team brings with them. Their weight combined with the boxes can't exceed the capacity of 1400. Assuming the elevator runs fine at that exact weight, you want to find the number of boxes, each of which contributes 40 pounds. This is given by the equation

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