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3 years ago

Which expression has the greatest value when x=3?

Mathematics

1 answer:

FrozenT [24]3 years ago

6 0

Answer:

3) $(2x)^{3}$

Step-by-step explanation:

x = 3

1) $2x^{3}$

2 x $3^{3}$

= 54

2) $2x^{3} + 5$

2 x $3^{3}$ + 5

= 59

3) $(2x)^{3}$

(2 x 3 $)^{3}$

$6^{3}$

=216

4) $(x - 1)^{3}$

(3 - 1 $)^{2}$

$2^{3}$

= 8

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suppose the theoretical probability of winning a prize in the carnival game 0.18 based on this probability how many more custome

Harlamova29_29 [7]

The number of customers I would have expected to win the prize is 6.

<h3>How many more customers would I have expected to win the prize?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

Based on the probability, the number of customers I would have expected to win: 0.18 x 300 = 36

How many more people I would have expected to win : 36 - 30 = 6

Please find attached the complete question. To learn more about probability, please check: brainly.com/question/13234031

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2 years ago

in a given year, the rate of flu infection for the general public was 8.3%. And sample of 200 people who receive the flu vaccine

makkiz [27]

Answer:

$\fbox{\begin{minipage}{10em}Option A is correct\end{minipage}}$

Step-by-step explanation:

Step 1: Define significance level

In this hypothesis testing problem, significance levels α is selected: $0.05$ , the associated z-value from Laplace table:

Φ( $z$ ) = α - $0.5 = 0.05 - 0.5 = -0.45$

=> $z$ = $-1.645$

Step 2: Define null hypothesis ( $H_{0}$ ) and alternative hypothesis ( $H_{1}$ )

$H_{0}$ : rate of flu infection $p$ = 8.3% or 8.3/100 = 0.083

$H_{1}$ : rate of flu infection $p$ < 8.3% or 8.3/100 = 0.083

Step 3: Apply the formula to check test statistic:

$K = \frac{f - p}{\sqrt{p(1 - p)} } * \sqrt{n}$

with $f$ is actual sampling percent, $p$ is rate of flu infection of $H_{0}$ , $n$ is number of samples.

The null hypothesis will be rejected if $K < z$

Step 4: Calculate the value of K and compare with $z$

$K = \frac{(\frac{3.5}{100}) - 0.083}{\sqrt{0.083(1 - 0.083)} } * \sqrt{200} = -2.46$

We have $-2.46 < -1.645$

=>This is good evidence to reject null hypothesis.

=> The actual rate is lower. (As $H_{1}$ states)

Hope this helps!

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Answer:

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Step-by-step explanation:

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3 years ago

taxes aaron's mother purchases a new computer for $1750. if she claims a linear depreciation (loss of value) on the computer at

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3 years ago

Read 2 more answers

Evaluate g(4): g(x) = 8x2 + 9x – 7 A) 121 B) 135 C) 154 D) 157

Lunna [17]

Answer:

g(4) = 157

Step-by-step explanation:

Substitute 4 for x in g(x) = 8x^2 + 9x – 7, obtaining:

g(4) = 8(4)^2 + 9(4) - 7 = 128 + 36 - 7 = 157

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3 years ago