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Novay_Z [31]
3 years ago
12

What is the solution to the equation √x^2+2x-25=√x+5 x = –6 x = 5 x = 6, x = –5 x = –6, x = 5

Mathematics
1 answer:
Dimas [21]3 years ago
4 0

Answer:

x = 5, -6

Step-by-step explanation:

Step 1: Write out equation

x² + 2x - 25 = x + 5

Step 2: Move everything to one side

x² + x - 30 = 0

Step 3: Factor

(x - 5)(x + 6) = 0

Step 4: Find roots

x - 5 = 0

x = 5

x + 6 = 0

x = -6

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What ordered pair is closest to a local minimum of the
grin007 [14]

Answer:

(2,1) aka D

Step-by-step explanation:

6 0
3 years ago
How to do the problem
MrMuchimi
Order of operations are:
<span>1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
<span>4. Addition and Subtraction (from left to right)

So, on your first one:
Parentheses first:
8(3+4)-2*8/(5-3)
8(7)-2*8/(2)

There are no exponents so multiplication and division:
56-16/2
56-8

Finally, addition and subtraction:
56-8=48

Your second problem is a bit more complicated but follows the same rules:
</span></span>( 8^{2}+(13-4) ^{2} )/5
<span><span>
Parentheses first:
</span></span>( 8^{2}+ 9^{2})/5)
<span><span>
Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5

Now back to parentheses:
(145)/5

Division:
145/5=29

Hope that helps</span></span>
8 0
3 years ago
-q2 - r2+ 3s<br> if q = 9, r = -6, s = -20<br> how do I solve this?
ANEK [815]

Step-by-step explanation:

-9(2)-(-6)(2)+3(-20)

(−9)(2)−(−6)(2)+(3)(−20)

=−18−(−6)(2)+(3)(−20)

=−18−(−12)+(3)(−20)

=−6+(3)(−20)

=−6+−60

=−66

6 0
3 years ago
1.) (2)(8+2i)= <br> Multiplying complex numbers
Nutka1998 [239]
Your answer is 16+4i
4 0
3 years ago
Read 2 more answers
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
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