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Elena L [17]
3 years ago
8

Evaluate x – 2y if x = –3 and y = –6.

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0
X - 2y
-3 - 2(-6)
-3 + 12
9
Doss [256]3 years ago
4 0
X - 2y 

x = -3 and y = -6

-3 - 2(-6)
-3 + 12
9

Answer: 9
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Create a factorable polynomial with a GCF of 2. Rewrite that polynomial in two other equivalent forms. Explain how each form was
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 4x^2 + 8x + 12

Equivalent forms: x^2 + 2x + 3 and 8x^2 + 16x + 24.

The first equivalent form was created by dividing each term by 2, and the second equivalent form was created by multiplying each term by 2.
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3 years ago
Simplifique a expressão 10ny-10x+10ny+10y
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Responder:

10 (2ny- (x-y))

Explicación paso a paso:

Dada la expresión 10ny-10x + 10ny + 10y, para simplificar la expresión, se deben seguir los siguientes pasos;

Paso 1; Separa la expresión en términos similares

= 10ny-10x + 10ny + 10y

= (10ny + 10ny) - (10x + 10y)

Paso 2: Factoriza los valores comunes en ambos paréntesis

10ny (1 + 1) - 10 (x-y)

= 10ny (2) - 10 (x-y)

= 20ny - 10 (x-y)

Factoriza nuestro valor común en ambos términos:

= 10 (2ny- (x-y))

3 0
3 years ago
What is the value of x?<br><br> 20<br> 35<br> 60<br> 70
aksik [14]

Answer:

its 60. u gotta know this stuff man

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3 years ago
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Find BC. PLEASEEE HELP
Cerrena [4.2K]

Answer:

Concept: Geometric Identities

  1. We want BC
  2. We will use geometric identities to get our value
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3 years ago
The strength of an aluminum alloy is normally distributed with mean 10 gigapascals (GPa) and standard deviation 1.4 GPa. What is
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Answer:

The first quartile of the strengths of this alloy is 9.055 GPa.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The strength of an aluminum alloy is normally distributed with mean 10 gigapascals (GPa) and standard deviation 1.4 GPa.

This means that \mu = 10, \sigma = 1.4

What is the first [lower] quartile of the strengths of this alloy?

This is the 100/4 = 25th percentile, which is X when Z has a pvalue of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 10}{1.4}

X - 10 = -0.675*1.4

X = 9.055

The first quartile of the strengths of this alloy is 9.055 GPa.

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3 years ago
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