ANSWER:
________
Line q = 3
Line v = -1/2
FORMULA
__________
y2 - y1 / x2 - x1
EXPLANATION:
_____________
First, we need to find the slope for line a only
We need to select two points from line q. The ones I selected are (-3,18) and (2,33)
y2 = 33
y1 = 18
x2 = 2
x1 = -3
33 - 18 = 15
2 - -3 = 5
15/5 = 3
Next, we need to find the slope for line v.
The two points I picked are (0,8) and (10,3)
y2 = 8
y1 = 3
x2 = 0
x1 = 10
8 - 3 = 5
0 - 10 = -10
5/-10 = -1/2
And that’s how you get your answer :)
PUN OF THE DAY
_______________
Why did Adele cross the road? To say hello from the other side.
I hoped this helped! And have a •AMAZING• day :3
Answer:
8 packs of bottled water and 14 packs of candy bars
Step-by-step explanation:
Provided,
Each pack of water bottles = 35 bottles
Each pack of candy = 20 candy
Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,
Purchase quantity of candy packs shall be more than the pack of water bottles.
Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.
In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.
Accordingly
Option 3
8 packs of water bottle = 
14 packs of candy = 
Since the quantities of water bottles and candies are same this is an opt answer.
Not sure, there is no graph with it. I just edited the question to fix the formatting and to add in info that got cut off when iI pasted it in.
These are two questions and two answers.
1) Problem 17.
(i) Determine whether T is continuous at 6061.
For that you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.
a) T(x) = 0.10x if 0 < x ≤ 6061
T (6061) = 0.10(6061) = 606.1
b) limit of Tx when x → 6061.
By the left the limit is the same value of T(x) calculated above.
By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)
⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10
Since both limits and the value of the function are the same, T is continuous at 6061.
(ii) Determine whether T is continuous at 32,473.
Same procedure.
a) Value at 32,473
T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26
b) Limit of T(x) when x → 32,473 from the right
Limit = 5360.26 + 0.26(x - 32,473) = 5360.26
Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.
(iii) If T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.
2) Problem 18.
a) Statement Sk
You just need to replace n for k:
Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2
b) Statement S (k+1)
Replace
S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2
Simplification:
1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2
k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2
Do the operations on the left side and you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.
With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.
Answer:
367
Step-by-step explanation:
367 because it is positive
