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aliina [53]
2 years ago
5

Some can help me Plis......

Mathematics
1 answer:
inn [45]2 years ago
7 0
Solve for the value of Y using the first equation, 3x-7, and then plug in 3x-7 wherever you see Y, because Y=3x-7. You can find X and then use that value of X and plug it into the equation to solve for Y
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<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula
dsp73
<h3>Solution:</h3>

( \sqrt{2}  + 1)(5 +  \sqrt{2}) \\  =  \sqrt{2}  (5 +  \sqrt{2} ) + 1(5 +  \sqrt{2} ) \\  = 5 \sqrt{2}  + 2 + 5 +  \sqrt{2}  \\  = 7 + 6 \sqrt{2}

<h3>Answer:</h3>

7 + 6√2

5 0
3 years ago
Read 2 more answers
Cassandra wants to solve the Quetion 30 equals 2/5 Pete. What operation should she perform to isolate the variable
BartSMP [9]
It sounds like you are setting up the equation below.
(2/5)P = 30

To solve this equation for P, you would multiply both sides of the equation by 5/2.
5 0
3 years ago
HEY can some please help me out I will give you BRAINLEST!!!
kondaur [170]

Answer:

b the second 1

Step-by-step explanation:

4 0
3 years ago
Can someone please help its due soon.
docker41 [41]

Answer:

the 4th one is the answer

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The quadratic function below has an axis of symmetry through x = -4; a vertex at (-4, -9) and zeroes at x = -7 and x = 0.
Pavlova-9 [17]

Answer:

True

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 9), thus

y = a(x + 4)² - 9

To find a substitute the coordinates of the zero (- 7, 0) into the equation.

0 = a(- 7 + 4)² - 9, that is

0 = 9a - 9 ( add 9 to both sides )

9a = 9 ( divide both sides by 9 )

a = 1, thus

y = (x + 4)² - 9 ← expand factor using FOIL

y = x² + 8x + 16 - 9

y = x² + 8x + 7

4 0
2 years ago
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