A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
Answer:
The answer is "
"
Step-by-step explanation:
That's why the answer is 
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Starting temperature = - 5°F
Temperature at midday =increase in temperature by 78°F = (starting temperature + 78°F)
Temperature at nightfall = decrease in temperature by 32°F = ( temperature at midday - 32°F)
Temperature at midday:
(-5°F + 78°F) = 73°F
Temperature at nightfall:
(Temperature at midday - 32°F)
(73°F - 32°F) = 41°F
Answer:
B
Step-by-step explanation:
yeah just pick B man lol
The foci need to be equal distances from the center of the eclipse.
See the attached picture. I marked off all the points that were given as choice and from this you can see that that (-5,-4) and (-5,2) are both 3 units away from the center.
The answer is: (-5,-4) and (-5,2)
