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2 years ago

Solution of 3x2 = 7x − 3?

Mathematics

1 answer:

yan [13]2 years ago

5 0

x = 9/7 ( aka 1.286)

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Please help! I’m not good with y=mb+x

3241004551 [841]

Answer:

m = -4

b = -12

Step-by-step explanation:

First, identify the slope-intercept form:

y = mx + b

y = -4x - 12

Whereas m = slope and b = y-intercept.

Slope is the steepness of the line.

The y-intercept is where the line intersects the y axis.

8 0

3 years ago

Read 2 more answers

Which description best compares the graphs of these two functions?

s2008m [1.1K]

Answer:

1st option, they have the same y-intercept

Step-by-step explanation:

they do not have the same x-intercept

'A' is linear

'B' has a less steep slope

8 0

2 years ago

Question number 8. Prove that 3 + √5 is an irrational number.

Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

$\\ \sf \: 3 + \sqrt{5} = \frac{a}{b} \\ \\ \qquad \: \tiny \sf{(where \: \: a \: \: and \: \: b \: \: are \: \: integers \: \: and \: \: b \: \neq \: 0)} \\$

$\\ \sf \: \sqrt{5} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \\$

Since, a, b and 3 are integers. So,

$\\ \sf \: \frac{p - 3b}{b} \\ \\ \qquad \tiny \sf{ \: (is \: \: a \: \: rational \: \: number \:) } \\$

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

$\\$

Hence, 3 + √5 is an irrational number.

7 0

2 years ago

HELP HELP!!

Goryan [66]

Answer:

Step-by-step explanation:

$p_1:~~y = x^2+2\\p_2:~~y = 3x^2+2\\ \\ V{p_1} = \Big(-\dfrac{b}{2a}, -\dfrac{\Delta}{4a}\Big) = \Big(-\dfrac{0}{2}, -\dfrac{0^2-4\cdot 2}{4}\Big) = \Big(0,2\Big) \\ \\ Vp_2 = \Big(x_V, -\dfrac{\Delta}{4a}\Big) = \Big(0, -\dfrac{0^2-4\cdot 3 \cdot 2}{4\cdot 3}\Big) = \Big(0,2\Big) \\ \\ \\ \text{The distance is }0,~~\text{Because the vertices are equal.}$

7 0

2 years ago

Help me plz thank you but try to put the right answer

Sedbober [7]

Answer:

Option D is correct.

Step-by-step explanation:

Have a nice day. ;-)

3 0

2 years ago