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mrs_skeptik [129]
3 years ago
10

Just do number 12 please

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0
Please make it clear:)
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Shannon went to the candy store and bought 6 1/5 pounds of candy. If 5/6 of Shannon‘s candy was chocolate, how many pounds of ch
ladessa [460]

Answer:

5 11/30 pounds

Step-by-step explanation:

6 1/5=31/5

= 31/5 - 5/6    (LCM=30)

= 186/30 - 25/30

= 161/30

= 5 11/30 pounds.

Hope this is helpful. :)

4 0
2 years ago
Mrs. Wong has 144 tiles that she is going to place on her square kitchen floor. If the tiles are $3.79 each, how much did Mrs. W
PolarNik [594]

Answer:

Mrs. Wong spend $545.76 on tiles.

Step-by-step explanation:

Mrs. Wong has 144 tiles that she is going to place on her square kitchen floor. If the tiles are $3.79 each, how much did Mrs. Wong spend on tile?

we are given

number of ties=144

cost of one tie=3.79 dollar

we have to find

total cost of 144 ties

for this we will multiply 144 by 3.79

multiplying 144 by 3.79 gives=144*3.79

it other words

one tile cost=$3.79

and for 144 ties cost

multiplying 144 on both sides

144 tiles cost=3.79*144=$545.76

8 0
3 years ago
Read 2 more answers
Solve the compound inequality 3x + 4 ≤ 7
Ierofanga [76]

Answer:

x ≤ 1

Step-by-step explanation:

3x+4≤ 7

3x + 4 - 4 ≤ 7 - 4

3x≤3

x ≤ 1

3 0
3 years ago
-4. (5 + 1) -3 + 3+ 2
antiseptic1488 [7]

Answer:

-13

Step-by-step explanation:

7 0
2 years ago
A number cube has faces numbered 1 through 6, and a coin has two sides, "heads" and "tails". The
Mama L [17]

Answer:

The <em>required probability</em> is \dfrac{1}{12}.

Step-by-step explanation:

Let <em>A </em>be the event of rolling the number cube.

Let <em>B</em> be the event of tossing the coin.

Total number of possibilities of rolling the number cube and tossing the coin are <em>12 </em>here.

\{(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)\}

where <em>H</em> means Head on toss of coin and <em>T</em> means Tails on toss of coin.

Formula for probability of an event <em>E</em> is:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, we have to find the probability of event 'E' i.e. getting a 6 on number cube and heads on coin.

Number of favorable cases are <em>1 </em>and total cases are <em>12</em>.

\Rightarrow P(E) = \dfrac{1}{12}

6 0
2 years ago
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