<span>5t=3b+660....and ... 2t+5b=450

from the first we can see that t=(3b+660)/5 and using this value in the second...

(6b+1320)/5+5b=450 making all have common denominator..

6b+1320+25b=2250

31b=930

b=30...and since 2t+5b=450

t=150</span>

4 0

3 years ago

A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit

aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

$2x+9y=101$

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0

3 years ago