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anyanavicka [17]
3 years ago
5

Ryan made a $3ooo down paymen tona car.The total coast of the car was $7500.he made 36 equal monthly payment to pay the car in f

ull.How much did Ryan pay per month??. (HELP PLZZ)2 step equation word problem
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Ryan payed $125 per month. Steps below.

7,500 - 3,000 = 4,500

4,500 / 36 = 125.

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The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016
hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N(\mu=4016 , \sigma^{2} = 532^{2})

The standard normal z distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( \frac{X-\mu}{\sigma} < \frac{5026-4016}{532} ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

5 0
3 years ago
`h(t)=-5t^{2}+10t+3`
Ipatiy [6.2K]
Solve the equation for
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−
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2
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20
h
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160
10
8 0
3 years ago
Can someone tell me what the intersection on the line is ??
algol13
The intersection is at (2,-1)
7 0
3 years ago
Read 2 more answers
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
3 years ago
If the textbook weight 19.6 newtons on venus, what is the strenght of gravity on that planet?
victus00 [196]

Answer:

8.91m/s²

Step-by-step explanation:

If you were referring to the question :

If a 2.2 kg textbook weighs 19.6 newtons on Venus, what is the strength of gravity on that planet then read on.

Weight is the force of gravity on an object and it can be computed using the formula:

W = mg

where:

W = weight (N)

m = mass (kg)

g = acceleration due to gravity

So we know the weight and the mass of the object, all we do is plug it into our formula and solve for what we do not know.

W = mg\\\\19.6N = (2.2kg)(g)\\\\ \dfrac{16.6N}{2.2kg} = g\\\\8.91m/s^{2} = g

6 0
3 years ago
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