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almond37 [142]
3 years ago
6

If the textbook weight 19.6 newtons on venus, what is the strenght of gravity on that planet?

Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

8.91m/s²

Step-by-step explanation:

If you were referring to the question :

If a 2.2 kg textbook weighs 19.6 newtons on Venus, what is the strength of gravity on that planet then read on.

Weight is the force of gravity on an object and it can be computed using the formula:

W = mg

where:

W = weight (N)

m = mass (kg)

g = acceleration due to gravity

So we know the weight and the mass of the object, all we do is plug it into our formula and solve for what we do not know.

W = mg\\\\19.6N = (2.2kg)(g)\\\\ \dfrac{16.6N}{2.2kg} = g\\\\8.91m/s^{2} = g

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Step-by-step explanation:

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What is the standard form of 1.46e-6
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astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

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Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

Simplify:

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b. one x-int at 3

this means that the equation will factor to:

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FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

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c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

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FOIL:

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a = 1, b = 0, c = -1

e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

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FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

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4

Step-by-step explanation:

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