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almond37 [142]
3 years ago
6

If the textbook weight 19.6 newtons on venus, what is the strenght of gravity on that planet?

Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

8.91m/s²

Step-by-step explanation:

If you were referring to the question :

If a 2.2 kg textbook weighs 19.6 newtons on Venus, what is the strength of gravity on that planet then read on.

Weight is the force of gravity on an object and it can be computed using the formula:

W = mg

where:

W = weight (N)

m = mass (kg)

g = acceleration due to gravity

So we know the weight and the mass of the object, all we do is plug it into our formula and solve for what we do not know.

W = mg\\\\19.6N = (2.2kg)(g)\\\\ \dfrac{16.6N}{2.2kg} = g\\\\8.91m/s^{2} = g

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QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

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f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

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