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frutty [35]
3 years ago
7

There are 14 dogs in a particular class at a dog show. Blue, red, yellow, and white ribbons will be awarded to the first through

fourth place finishers, respectively. In how many different ways can the ribbons be awarded?
1001
6006
24024
38416
Mathematics
1 answer:
stira [4]3 years ago
4 0
There are 14 possibilities for first place.
There are 13 possibilities for second place, since a dog can't get both first and second place.
There are 12 possibilities for third place, since a dog can't get both first, second, and third place.
There are 11 possibilities for fourth place, since a dog can't get both first, second, third, and fourth place.

Multiply them together and get 24024 possibilities.

Hope this helps!

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Answer:

First one: Function

Second one: not a function (a function cannot have two outputs)

Third one: Function

Last one: Not a function (doesn't pass vertical line test)

Step-by-step explanation:

Hope it helps!

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One of every four doctors recommended Tylenol. If there are 2250 doctors, approximately how many recommended the medicine ?
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The answers is B 560
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Reviewing Imaginary Numbers. Simplify I^12
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Answer:

1

Step-by-step explanation:

i^{12}= i^{2} *i^{2} *i^{2} *i^{2} *i^{2} *i^{2}

Remember that i^{2}=-1

Plug it in:

i^{12}= (-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2} *(-1)^{2}

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What x what = 1600 pls help me
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Step-by-step explanation:

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Suppose that, for a particular social networking company, the annual revenue from rich media advertisements, in millions of doll
Juli2301 [7.4K]

Answer:

a. Revenue of the company at the beginning of 2010 is 75 million dollar (loss)

b. Rate at which the revenue changing in the year 2010 is 76 million dollar per year ( decreasing)

Step-by-step explanation:

For part a,

Given that x is the number of years at the beginning of 2007.

Therefore, x=0 for year 2007.

Hence at the year 2010 value of x will be x=3.

Substitute the value of x=3 in R(x),

R\left(x\right)=-x^{4}+8x^{3}-38x^{2}+44x

R\left(x\right)=-\left(81\right)+8\left(27\right)-38\left(9\right)+132

R\left(x\right)=-81+216-342+132

R\left(x\right)=-75

Negative sign indicates that there is loss of revenue at the start of the year 2010

Therefore, there is loss of revenue at the beginning of 2010 which is 75 million dollar.

For part b,

To calculate rate, differentiate the given function with respect to x.

\dfrac{d}{dx}R\left(x\right)=\dfrac{d}{dx}\left (-\left(x\right)^{4}+8\left(x\right)^{3}-38\left(x\right)^{2}+44\left(x\right)\right)

Applying sum and difference rule of derivative,

\dfrac{d}{dx}R\left(x\right)=-\dfrac{d}{dx}\left(x^4\right)+\dfrac{d}{dx}\left(8x^3\right)-\dfrac{d}{dx}\left(38x^2\right)+\dfrac{d}{dx}\left(44x\right)

Applying constant multiple rule of derivative,

\dfrac{d}{dx}R\left(x\right)=-\dfrac{d}{dx}\left(x^4\right)+8\dfrac{d}{dx}\left(x^3\right)-38\dfrac{d}{dx}\left(x^2\right)+44\dfrac{d}{dx}\left(x\right)

Applying power rule of derivative,

\dfrac{d}{dx}R\left(x\right)=-\left(4x^{4-1}\right)+8\left(3x^{3-1}\right)-38\left(2x^{2-1}\right)+44\left(1x^{1-1}\right)

\dfrac{d}{dx}R\left(x\right)=-4\left(x^{3}\right)+8\left(3x^{2}\right)-38\left(2x^{1}\right)+44

\dfrac{d}{dx}R\left(x\right)=-4x^3+24x^2-76x+44

Substituting the value x=3,

\dfrac{d}{dx}R\left(x\right)=-4\left(3\right)^3+24\left(3\right)^2-76\left(3\right)+44

\dfrac{d}{dx}R\left(x\right)=-4\left(27\right)+24\left(9\right)-76\left(3\right)+44

\dfrac{d}{dx}R\left(x\right)=-108+216-228+44

\dfrac{d}{dx}R\left(x\right)=-76

Negative sign indicates that rate is decreasing.

Rate at which the revenue is changing in the year 2010 is 76 million dollar per year.

8 0
3 years ago
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