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frutty [35]
3 years ago
7

There are 14 dogs in a particular class at a dog show. Blue, red, yellow, and white ribbons will be awarded to the first through

fourth place finishers, respectively. In how many different ways can the ribbons be awarded?
1001
6006
24024
38416
Mathematics
1 answer:
stira [4]3 years ago
4 0
There are 14 possibilities for first place.
There are 13 possibilities for second place, since a dog can't get both first and second place.
There are 12 possibilities for third place, since a dog can't get both first, second, and third place.
There are 11 possibilities for fourth place, since a dog can't get both first, second, third, and fourth place.

Multiply them together and get 24024 possibilities.

Hope this helps!

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What is the solution to –2(8x – 4) < 2x + 5?
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The solution to –2(8x – 4) < 2x + 5 is x > 1/6

<h3>How to solve the inequality?</h3>

The expression is given as:

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4 0
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