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madam [21]
3 years ago
7

Find the areas of the sectors formed by ZDFE. Round your answers to the nealest hundredth.

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

Step-by-step explanation:

Area of the sector is modeled by the expression = \frac{\theta}{360}(\pi ) r^{2}

Here, θ = central angle subtended by the arc

r = Radius of the circle

Area of the red sector = \frac{137}{360}(\pi)(28)^{2}

                                     = 937.311

                                     ≈ 937.31 m²

Therefore, area of the red sector is 937.31 m².

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1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)
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Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that \mu = 8, \sigma = 1.5

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 8}{1.5}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 6.5

Z = \frac{X - \mu}{\sigma}

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Z = -1

Z = -1 has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

7 0
3 years ago
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