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natita [175]
3 years ago
5

What is the pressure inside a cylinder when the volume changes from 12.49 dm3 to 47.32 dm3 with an initial pressure of 7.257 x 1

02 kPa? The temperature of the cylinder remained constant at 37.1ºC
Chemistry
1 answer:
zvonat [6]3 years ago
4 0

Answer:

<u>The pressure inside becomes : 202.646 KPa</u>

Explanation:

Given ,

  • <em>The temperature inside the cylinder is constant</em>
  • <em>The number of moles of the gas inside the cylinder will also be constant because it's a closed one.</em>

<em>Now according Boyle's law , </em>

  • <em>The pressure of a gas of fixed mass is inversely proportional to its volume at a constant temperature.</em>

Thus ,

P_1V_1=P_2V_2\\

  • P_1 is the initial pressure 7.257*102*10^3 Pa
  • P_2 is what we need to find
  • V_1 = 12.49dm^3 - initial volume
  • V_2 = 47.32dm^3 - final volume

∴

7.527*102*10^3*12.49=P_2*47.32\\P_2=2.02646*10^5Pa

The pressure inside becomes : 202.646 KPa

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