Question

What is the pressure inside a cylinder when the volume changes from 12.49 dm3 to 47.32 dm3 with an initial pressure of 7.257 x 102 kPa? The temperature of the cylinder remained constant at 37.1ºC

Answer 1

Answer:

The pressure inside becomes : 202.646 KPa

Explanation:

Given ,

• The temperature inside the cylinder is constant
• The number of moles of the gas inside the cylinder will also be constant because it's a closed one.

Now according Boyle's law ,

• The pressure of a gas of fixed mass is inversely proportional to its volume at a constant temperature.

Thus ,

$P_1V_1=P_2V_2$

• $P_1$ is the initial pressure $7.257*102*10^3 Pa$
• $P_2$ is what we need to find
• $V_1 = 12.49dm^3$ - initial volume
• $V_2 = 47.32dm^3$ - final volume

∴

$7.527*102*10^3*12.49=P_2*47.32\\P_2=2.02646*10^5Pa$

The pressure inside becomes : 202.646 KPa