Answer:
After 6sec 5 atoms will be left.
Explanation:
Given data:
Total atoms of Highlinium = 40
Half life = 2 sec
Atoms left after 6sec = ?
Solution:
First of all we will calculate the number of half lives passes during 6sec.
Number of half lives = Time elapsed/ half life
Number of half lives = 6 sec / 2sec
Number of half lives = 3
Now we will calculate the number of atoms left
At time zero = 40 atoms
At 1st half life = 40 atoms/2 = 20 atoms
At 2nd half life = 20 atoms/2 = 10 atoms
At 3rd half life = 10 atoms / 2 = 5 atoms
Thus, after 6sec 5 atoms will be left.
Answer:
Any organic compound with a carboxyl functional group—a carbon with one double bond to an oxygen and a single bond to another oxygen, which is then connected to a hydrogen—is referred to as a carboxylic acid.
Explanation:
An organism that consists of one cell
Answer:
c. abc₃
Step-by-step explanation:
1. a atoms
There are eight corners, each containing an a atom.
No. of a atoms = 8 × ⅛
No. of a atoms = 1
=====
2. b atoms
There is one central b atom.
=====
3. c atoms
There are six faces, each containing a c atom.
No. of a atoms = 6 × ½
No. of c atoms = 3
=====
4. Formula
The simplest formula is abc₃.
Answer : The final temperature is, 
Explanation :
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of water at 
= 150 g
= mass of water at 
= 100 g
= final temperature = ?
= temperature of lead = 
= temperature of water = 
= same (for water)
Now put all the given values in equation (1), we get
![150\times (T_{final}-363)=-[100\times (T_{final}-303)]](https://tex.z-dn.net/?f=150%5Ctimes%20%28T_%7Bfinal%7D-363%29%3D-%5B100%5Ctimes%20%28T_%7Bfinal%7D-303%29%5D)
Therefore, the final temperature is,
