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3 years ago

What is the movement of thermal energy?

Chemistry

1 answer:

V125BC [204]3 years ago

3 0

Thermal energy is atype of movement energy wich is exist in equilibrium.

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At 25 ∘C , the equilibrium partial pressures for the reaction were found to be PA=5.16 bar, PB=5.04 bar, PC=4.11 bar, and PD=4.8

erastova [34]

Answer: 5.85kJ/Kmol.

Explanation:

The balanced equilibrium reaction is

$A(g)+2B(g)\rightleftharpoons 4C(g)+D(g)$

The expression for equilibrium reaction will be,

$K_p=\frac{[p_{D}]\times [p_{C}]}^4{[p_{B}]^2\times [p_{A}]}$

Now put all the given values in this expression, we get the concentration of methane.

$K_p=\frac{(4.85)\times [(4.11)^4}{(5.04)^2\times (5.16)}$

$K_p=10.6$

Relation of standard change in Gibbs free energy and equilibrium constant is given by:

$\Delta G^o=-2.303\times RT\times \log K_c$

where,

R = universal gas constant = 8.314 J/K/mole

T = temperature = $25^0C=(25+273)K=298 K$

$K_c$ = equilibrium constant = 10.6

$\Delta G^o=-2.303\times 8.314\times 298\times \log (10.6)$

$\Delta G^o=5850.23J/Kmol$

$\Delta G^o=5.85kJ/Kmol$

Thus standard change in Gibbs free energy of this reaction is 5.85kJ/Kmol.

3 0

3 years ago

Help? i need to finish my assignment :>

earnstyle [38]

Answer:

B 2

Explanation:

I checked it and it’s right hope this helps!!

6 0

3 years ago

Consider the following balanced reaction. What mass (in g) of CO2 can be formed from 288 mg of H2CO3 → H2O CO2 A 14.01 g sample

WINSTONCH [101]

Answer:

0.198 g CO2 plz mark me brainliest

Explanation:

6 0

3 years ago

To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?

CaHeK987 [17]

Answer:

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Explanation:

Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.

In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a solution it is fulfilled:

Ci* Vi = Cf* Vf

where:

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

In this case:

Ci= 1.40 M
Vi= 20 mL
Cf= 0.088 M
Vf= ?

Replacing:

1.40 M* 20 mL= 0.088 M* Vf

Solving:

$Vf=\frac{1.40 M* 20 mL}{0.088 M}$

Vf= 318.18 mL

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

7 0

3 years ago

In nuclear physics what units are used to measure the radius of an Atom

Paul [167]

I'm sorry I'm not quit sure

7 0

3 years ago