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aleksandr82 [10.1K]
3 years ago
13

Find the area of the figure.

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

area of figure = area of rectangle + area of triangle

area of rectangle= length × width

6×4

24yd²

area of triangle= 1/2×base×height

1/2×3×4

3×2

=6yd²

area of figure= 24+6

= 30yd²

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The Fun Committee is hosting the Annual City Festival. Jennifer is in charge of the committee and is planning a race to raise mo
nadya68 [22]

Answer: Hello your question some data but i will provide a general solution based on the scope of your question making some suggestions as well

answer : Summation of displacements ( back and forth distance ) / Number of Runners

Step-by-step explanation:

Given that ; the aim of the race is to raise money

The number of miles/ distance covered will determine how much money that would be raised

Formula to resolve the problem =  Summation of displacements ( back and forth distance ) / Number of Runners

<em>Lets assume: ( example ) </em>

<em> Distance between the Park and the City hall is = 6 miles </em>

<em>Number of runners = 4</em>

<em>Given that the runners Run  from the Park to the City hall and then run back</em>

<em>Total miles covered by each runner = ( 6 + 6 )/ 4  = 12/4 = 3 miles </em>

4 0
3 years ago
Find the standard deviation of the data, 12, 19, 9.
jek_recluse [69]

Answer:

4.19

Step-by-step explanation:

Find the mean:

\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}

Find the standard deviation:

\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19

4 0
2 years ago
Use the distributive property to simplify the expression below:
Lorico [155]
4x + 2x + 2
= 6x + 2

So the answer is B
8 0
3 years ago
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Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply.
mrs_skeptik [129]

Answer:

For positive values of x, g(x) > h(x).  

For negative values of x, g(x) > h(x).

Step-by-step explanation:

For any value of x g(x) is always greater than h(x) and for any value of x, h(x) will always be greater than g(x) are not true.

The given function is:

g(x) = x^2 and h(x) = –x^2

x=0

g(0)=(0)^2 = 0

h(0)= -(0)^2 = 0

Now check the condition for x = -1

put x =-1 in the given functions.

g(x)=x^2

g(-1) = (-1)^2 = 1

h(x)= -x^2

h(-1) =  -(-1)^2 = -1

g(x)>h(x)

Now take a positive value of x= 3

Put the value in the given functions:

g(3) = (3)^2 = 9

h(3) = -(3)^2 = -9

g(x)>h(x)

For positive values of x, g(x) > h(x).  

For negative values of x, g(x) > h(x)....

4 0
3 years ago
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Its literally not fair...
Bess [88]

Answer:

I thought you were quoting danganronpa for a second ...

I hope you feel better!!

Step-by-step explanation:

5 0
3 years ago
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