Answer:
12/13
Step-by-step explanation:
There are 52 cards in the deck
4 are aces
That leaves 52-4 or 48 that are not aces
P(not an aces) = cards that are not aces / total
= 48/52
=12/13
Answer:
Step-by-step explanation:
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
Add the polynomials together:
(5x-2)+(2x-3)+(4x+3)
Combine like terms:
(5x+2x+4x) + (-2+-3+3) = 11x-2
So the answer is D.
