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Orlov [11]
3 years ago
8

The above diagram illustrates the short run cost curves for Sarah Mat, a rice farmer in Queensland. Calculate the profit or loss

for Sarah Mat and, examine the key characteristics for perfect competition firm with reference to Sarah’s farm. (10 Marks)
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

3500

Step-by-step explanation:

with reference to Sarah’s farm under the characteristics for perfect competition, the equilibrium of the firm will be at where the marginal cost curve intersects the marginal revenue or average revenue curves from below.

Under perfect competition AR = MR

as per given diagram equilibrium of the firm will be at where MR = AR = MC

with this intersection equilibrium quantity 500 rice ( Bags/month)

and the equilibrium price will be 40 (AUD)/20KG bag

Here ATC of the firm is less than its price, therefore the firm is making profits in the short-run.

Profit = Total revenue - Total cost

= P * Q - ATC * Q

= 40 * 500 - 33 * 500

= 20000 - 16500

= 3500

Hence, firm is making 3500 profit in the short-run

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Pls help due today!!!!!!
Agata [3.3K]

Answer: A

Step-by-step explanation:

For a line to be perpendicular, the slope should be the opposite reciprocal. The intercept doesn't matter, so we automatically know that it's A.

6 0
3 years ago
At a sale, dresses were sold for 36% of their original price. If the dresses originally cost $200 each, how much did a dress cos
Lubov Fominskaja [6]

Answer:

Each dress would cost 72

Step-by-step explanation:

36% of 200 is 72

5 0
3 years ago
Is it is it possible to have 43 pencils and divide the pencils into groups with the same number of pencils with none left over
anastassius [24]

we have given 43 pencils

we need to divide it equally so that none can be without groups.

we need to find the factors of 43.

we know that 43 is a prime number. which cannot be divided.so it is not possible to divide the 43 pencils with none left over .

6 0
3 years ago
Read 2 more answers
Assume the speed of vehicles along a stretch of I-10 has an approximately normal distribution with a mean of 81 mph and a standa
Pachacha [2.7K]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: speed of a vehicle along a stretch of I-10 (mph)

This variable has a normal distribution with mean μ= 81 mph and a standard deviation σ= 8 mph.

The speed limit in the said stretch is 65 mph.

You need to calculate the probability of picking a car at random and its speed be at most 65 mph, symbolically:

P(X≤65)

To reach the probability, you need to use the standard normal distribution. To standardize the value fo X you have to subtract the value of μ and then divide it by σ:

P(Z≤(65-81)/8)= P(Z≤-2.00)

Now you look for the corresponding probability in the table of the standard normal distribution, since the value is negative you have to use the left entry. The integer and first decimal numbers are in the first column and the second decimal number is in the first row.

P(Z≤-2.00)= 0.0228

I hope it helps!

3 0
3 years ago
Help me please I think the rate of change is 35 but don’t know how to graph I’m tenth grade
rusak2 [61]

Let x be the time in hours and y be the distance driven in miles. If x = 0, then no time has passed which means he can't drive anywhere. So y = 0 when x = 0. The first point is (0,0). Note: the y intercept is 0 as this is where the graph crosses the vertical y axis.

One hour later, he has driven 35 miles because 140/4 = 35. In other words, his speed is 35 miles per hour (mph). So we have the second point (x,y) = (1,35). Note: the rate of change is the same as the slope in this problem. Also the rate of change is the same as saying "speed" for this problem.

Plot the two points (0,0) and (1,35) and draw a straight line through the two points. Extend the line as far as you can. The graph is linear assuming he maintains his speed to be the the same throughout the whole trip.

4 0
3 years ago
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