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erastovalidia [21]

3 years ago

10

Simplify using order of operations: 2(5 – 8) x 42.

2 answers:

Katen [24]3 years ago

8 0

Hey there,

Lets solve this equation step by step,

First, <span>Simplify </span><span>5−8 </span><span>to </span><span>−3

</span> $2*-3x^4^2$

Simplify,

$-2*3x^4^2$

Simplify <span>2×3<span>x^42</span></span><span> to </span><span>6<span>x^<span>42

</span></span></span> $-6x^4^2$

GaryK [48]3 years ago

5 0

To solve, we will use PEMDAS.
Parenthesis first: 2(-3) x 42
There are no exponents
Multiply 2 by -3: -6 x 42
Multiply -6 by 42: -252
Your answer is -252. Remember to always use PEMDAS!

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Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

Zohar is using scissors to cut a rectangle with a length of 5x - 2 and a width of 3x + 1 out of a larger piece of paper. Which

kirza4 [7]

Answer:

2*(5x - 2) + 2*(3x+1) ; Perimeter = 62 centimeters

Step-by-step explanation:

2*(5x - 2) + 2*(3x+1) = 10x - 4 + 6x + 2

= 16x -2

If x = 4 , then Perimeter = 16*4 - 2 = 64 - 2 = 62 cm

4 0

3 years ago

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Murljashka [212]

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iren [92.7K]

- 3 - 8 = - 11
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3 years ago